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umka21 [38]
3 years ago
15

In pea plants Round (R) is a dominant trait and wrinkled nose (r) is a recessive trait. Which combination would result in wrinkl

ed seeds?
1. RR
2. Rr
3. rr
4. ww
Physics
2 answers:
Oliga [24]3 years ago
8 0
3 rr because you can only get wrinkly nose if you have to little r’s
bixtya [17]3 years ago
7 0
The answer is would be number 3 rr
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Nucleus A decays into the stable nucleus B with a half-life of 22.07 s. At t=0 s there are 1,293 A nuclei and no B nuclei. At wh
Alexeev081 [22]

Answer:

29.38 seconds

Explanation:

Half life, T = 22.07 s

No = 1293

Let N be the number of atoms left after time t

N = 1293 - 779 = 514

By the use of law of radioactivity

N=N_{0}e^{-\lambda t}

Where, λ is the decay constant

λ = 0.6931 / T = 0.6931 / 22.07 = 0.0314 decay per second

so,

514=1293e^{-0.0314t}

2.5155=e^{0.0314t}

take natural log on both the sides

0.9225 = 0.0314 t

t = 29.38 seconds

5 0
3 years ago
Diamond and graphite are both composed entirely of carbon yet graphite is soft and diamond is one of the hardest substances know
pogonyaev

Explanation:

This difference is because of the difference in arrangement of carbon atoms both graphite and Diamond.

Carbon atoms in graphite are arranged in layered form in an infinite array of layers. These layers are held together by a weaker force of attraction called vander waal's force of attraction such that layer's can slip over one another. Whereas in diamond carbon atoms are arranged tetrahedrally. Each carbon atom is attached to four carbon atoms with a bond angle of 109.5°. It is strong rigid three dimensional structure that results in infinite array atoms. This accounts for hardness of the diamond.

3 0
3 years ago
A beam of light converging to the point of 10 cm is incident on the lens. find the position of the point image if the lens has a
Verizon [17]

Answer:

beam of light converges to a point A. A lens is placed in the path of the convergent beam 12 cm from P.

To find the point at which the beam converge if the lens is (a) a convex lens of focal length 20 cm, (b) a concave lens of focal length 16 cm

Solution:

As per the given criteria,

the the object is virtual and the image is real (as the lens is placed in the path of the convergent beam)

(a) lens is a convex lens with

focal length, f=20cm

object distance, u=12cm

applying the lens formula, we get

f

1

=

v

1

−

u

1

⟹

v

1

=

f

1

+

u

1

⟹

v

1

=

20

1

+

12

1

⟹

v

1

=

60

3+5

⟹v=7.5cm

Hence the image formed is real, at 7.5cm from the lens on its right side.

(b) lens is a concave lens with

focal length, f=−16cm

object distance, 12cm

applying the lens formula, we get

f

1

=

v

1

−

u

1

⟹

v

1

=

f

1

+

u

1

⟹

v

1

=

−16

1

+

12

1

⟹

v

1

=

48

−3+4

⟹v=48m

Hence the image formed is real, at 48 cm from the lens on the right side.

6 0
2 years ago
Un bloque de m1= 2,00 kg está conectado con otro bloque de m2= 6,00 kg como se ve, las superficies son rugosas y su coeficiente
STatiana [176]

The answer is C on edge
3 0
3 years ago
Engineers are starting on a new project to develop technology. Which of these
Ilya [14]
The answer should be C. In this question
3 0
3 years ago
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