Answer:
No number answer; don't want to pull out a calculator lol
Explanation:
Capacitors are added in parallel; opposite of resistors.
So for 9, add 10 and 2.5 then do ((1/12.5)+(1/.3))^-1.
For 10, add 0.75 and 15 first, then the rest is the same idea as 9.
There will not be enough momentum from the first hill to cross another hill if he same or larger size because of the way potential energy and kinetic energy works it will not be able go as high as it could go on he fist hill.
<u>Voltage:</u>
It is basically the difference between the charges of the materials on the ends of the Wire
<em>also known as potential difference</em>
It is very similar to the movement of air, it moves from higher density to lower density. in this case, the change in density is the potential difference
So, since voltage is the difference between the charge available on the ends of a wire. Even if the wire splits in parallel circuit, the difference of the charges remains the same
<em>the more the potential difference, the faster electrons will move to the material with lower charge</em>
<u>Current:</u>
Current is the amount of electrons moving through a cross-section of a wire in a period of time
So basically, it is the amount of electrons that move across a given point on a wire in a period of time
If the wire splits, we will have the same amount of electrons moving through as they would if the wire was not split but now, the electrons passing are divided and hence, if we measure the current after the split, we will find that we have a lower current
that's because we have less charge moving through the cross-section of the wire since some of those electrons are moving through a different wire
That's why the current splits in a parallel circuit
Answer:
Option b. is correct
Explanation:
An RLC electrical circuit consists of constituent components: a resistor (R), an inductor (L), and a capacitor (C). A resistor, an inductor, and a capacitor are connected in series or parallel.
The impedances of the circuit elements depend on the frequency.
Both impedance magnitudes decrease when the frequency increases
