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4 years ago

A wave with a period of 1⁄3 second has a frequency of A. 67 Hz. B. 33 Hz. C. 300 Hz. D. 3 Hz.

1 answer:

3 0

A wave with a period of 1⁄3 second has a frequency of D. 3 Hz. To calculate this we will use the formula that represents the correlation between a frequency (f) and a time period (T): T = 1/f. Or: f = 1/T. The unit for the time period is second "s" while the unit for frequency is Hertz "Hz" (=1/s). We know that T = 1/3 s. That means that f = 1/(1/3s) = 3 1/s = 3 Hz.

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What could you detect using a magnet and iron filings?

Anton [14]

Answer:

A compass can detect a magnetic field and show its direction. Iron filings can show the shape of a magnetic field. A gaussmeter can detect a field and indicate its strength.

Explanation:

4 0

3 years ago

A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T

lesya [120]

Answer:

Impulse in the first collision is greater

Explanation:

u = Initial velocity of cart

v = Final velocity of cart

m = Mass of of cart

First collision

Impulse

$J=m(v-u)\\\Rightarrow J=m(0.3-(-0.3))\\\Rightarrow J=m(0.6)$

Second collision

Impulse

$J=m(v-u)\\\Rightarrow J=m(0-(-0.3))\\\Rightarrow J=m(0.3)$

Hence, the impulse in the first collision is greater than the second impact

7 0

4 years ago

Even in the most advanced circuits, we cannot oscillate electrons back and forth at that rate through wires. But we can oscillat

den301095 [7]

Answer:

the oscillations of the electrons must be in the 10⁸ Hz = 100 MHz range

Explanation:

The speed of a wave of radio, television, light, heat, all are manifestations of electromagnetic waves that are oscillations of electric and magnetic fields that support each other, the speed of all these waves is the same and the vacuum is equal to c = 3 108 m / s

All waves have a relationship between the speed of the wave, its frequency and wavelength

c = λ f

f = c /λ

for this case lam = 1 m

f = 3 10⁸/1

f = 3 10⁸ Hz

the oscillations of the electrons must be in the MHz range

It should be clarified that the speed of light in air is a little lower

n = c / v

v = c / n

the refractive index of vacuum is n = 1 and the refractive index of air is n = 1.000002

5 0

3 years ago

Richard is driving home to visit his parents. 135 mi of the trip are on the interstate highway where the speed limit is 65 mph .

Elis [28]

<h2>Answer:</h2>

He saves 13.2 minutes

<h2>Explanation:</h2>

Hey! The question is incomplete, but it can be found on the internet. The question is:

How many minutes did he save?

Let's call:

$t_{1}:Time \ at \ speed \ 65mph \\ \\ t_{2}:Time \ at \ speed \ 73mph \\ \\ v_{1}=65mph \\ \\ v_{2}=73mph$

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

$v=\frac{d}{t} \\ \\ d:distance \\ \\ t:time \\ \\ v:velocity \\ \\ t_{1}=\frac{d}{v_{1}} \\ \\ t=\frac{135}{65} \\ \\ t_{1}=2.07 \ hours$