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miskamm [114]
4 years ago
9

Write the electron configurations for the first 10 elements on the periodic table

Chemistry
1 answer:
dusya [7]4 years ago
4 0

Explanation:

H - 1s¹

He - 1s²

Li - 1s² 2s¹

Be - 1s² 2s²

B - 1s² 2s² 2p¹

C - 1s² 2s² 2p²

N - 1s² 2s² 2p³

O - 1s² 2s² 2p⁴

F - 1s² 2s² 2p⁵

Ne - 1s² 2s² 2p⁶

pls give me brainliest!!!

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Nana76 [90]

Answer:

Therefore, when an atom becomes a positive ion is pulls its electrons closer, decreasing is radius moreover, when it becomes a negative ion, it pulls its electrons closer and decreases the radius.

5 0
3 years ago
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.345 g of Fe2S3 if the percent yiel
GuDViN [60]

Answer:

25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃

Explanation:

Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.

0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):

0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>

Moles of Fe needed to produce these moles of Fe₂S₃ are:

1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =

<em>3.3189x10⁻³ moles of FeCl₃</em>

As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:

3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>

A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:

<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>

<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>

8 0
3 years ago
Structure can affect the Ka values for related acids. In the boxes below, draw the complete Lewis structure for a single ion of
Zigmanuir [339]

Answer:

Explanation: see attachment below

8 0
3 years ago
What is the correct balanced equation for the reaction that occurs when aqueous ammonium chloride reacts with aqueous barium nit
Setler [38]

Answer:

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + NH_{4}NO_{3}

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride  with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

5 0
3 years ago
I need help use e picture that’s the question I’m stuck on pleassse
aniked [119]

Answer:

1.14 M

Explanation:

grams/molar mass = ans. / volume

317/110.98=2.86/2.50=1.14 M

- Hope that helps! Please let me know if you need further explanation.

5 0
3 years ago
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