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mylen [45]
2 years ago
11

What would be the mass in grams of 0.300 moles of the ionic compound formed when magnesium metal reacts with oxygen

Chemistry
1 answer:
yarga [219]2 years ago
4 0

Answer:

Balanced Equation for reaction between Magnesium and Oxygen:

2Mg + O₂ --> 2MgO

Molar Mass of MgO is the atomic masses listed on the periodic table for the two elements Magnesium and Oxygen. Magnesium's molar mass is 24g/mol, and Oxygen's molar mass is 16g/mol. So MgO's molar mass would be 24 + 16 = 40g/mol.

The equation to find moles is:

moles \ = \ \frac{mass}{molar \ mass}

So if we rearrange this equation to find for mass:

mass = moles \ * \ molar \ mass

So you have to multiply 0.300 moles by 40, which gives you 12g

Meaning the mass of Magnesium Oxide is 12g.  

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Answer:

A. O=C=O and O≡C−O

Explanation:

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          When the electron distribution on the molecule become uneven like one molecule have more electron compare to other.Resonance occurs due to overlap of the orbitals.When electron flow through pi system then resonance occurs.

So the option A is correct.

A. O=C=O and O≡C−O

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3 years ago
How many moles of electrons must be transferred to plate out 110 g of manganese (MW ~ 55g/mol) from a solution of permanganate (
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Answer:

14 mol e⁻

Explanation:

Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese

8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)

Step 2: Calculate the moles corresponding to 110 g of manganese

The molar mass of Mn is 55 g/mol.

110 g × 1 mol/55 g = 2 mol

Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn

According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.

2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻

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Explanation:

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