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mylen [45]
2 years ago
11

What would be the mass in grams of 0.300 moles of the ionic compound formed when magnesium metal reacts with oxygen

Chemistry
1 answer:
yarga [219]2 years ago
4 0

Answer:

Balanced Equation for reaction between Magnesium and Oxygen:

2Mg + O₂ --> 2MgO

Molar Mass of MgO is the atomic masses listed on the periodic table for the two elements Magnesium and Oxygen. Magnesium's molar mass is 24g/mol, and Oxygen's molar mass is 16g/mol. So MgO's molar mass would be 24 + 16 = 40g/mol.

The equation to find moles is:

moles \ = \ \frac{mass}{molar \ mass}

So if we rearrange this equation to find for mass:

mass = moles \ * \ molar \ mass

So you have to multiply 0.300 moles by 40, which gives you 12g

Meaning the mass of Magnesium Oxide is 12g.  

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At 63.5 C the vapor pressure of H2O is 175 torr and that of ethanol is 400 torr. A solution is made by adding equal masses of H2
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Answer:

Moel fraction of ethanol in the solution = 0.28

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Let's use 100 g of each substance as a calculus basis. Knowing that the molar mass of water is 18 g/mol and the molar mass of ethanol is 46 g/mol, the number of moles (n = mass/molar mass) of each one is:

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The partial pressure of each substance can be found by the multiplication of the molar fraction by the vapor pressure, thus:

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So, the mole fraction of ethanol is:

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