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2 years ago

What would be the mass in grams of 0.300 moles of the ionic compound formed when magnesium metal reacts with oxygen

Chemistry

1 answer:

yarga [219]2 years ago

4 0

Answer:

Balanced Equation for reaction between Magnesium and Oxygen:

2Mg + O₂ --> 2MgO

Molar Mass of MgO is the atomic masses listed on the periodic table for the two elements Magnesium and Oxygen. Magnesium's molar mass is 24g/mol, and Oxygen's molar mass is 16g/mol. So MgO's molar mass would be 24 + 16 = 40g/mol.

The equation to find moles is:

$moles \ = \ \frac{mass}{molar \ mass}$

So if we rearrange this equation to find for mass:

$mass = moles \ * \ molar \ mass$

So you have to multiply 0.300 moles by 40, which gives you 12g

Meaning the mass of Magnesium Oxide is 12g.

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At 63.5 C the vapor pressure of H2O is 175 torr and that of ethanol is 400 torr. A solution is made by adding equal masses of H2

xxTIMURxx [149]

Answer:

Moel fraction of ethanol in the solution = 0.28

Vapor pressure of the solution = 238 torr

Mole fraction of ethanol in the vapor = 0.47

Explanation:

Let's use 100 g of each substance as a calculus basis. Knowing that the molar mass of water is 18 g/mol and the molar mass of ethanol is 46 g/mol, the number of moles (n = mass/molar mass) of each one is:

nw = 100/18 = 5.56 mol

ne= 100/46 = 2.17 mol

The total number of moles is 7.73 mol, so the mole fraction of ethanol is

2.17/7.73 = 0.28

The mole fraction of water must be 0.72, so if we assume that the solution is ideal, by the Raoult's law, the solution vapor pressure is the sum of the multiplication of the mole fraction by the vapor pressure of each substance, thus:

P = 0.28*400 + 0.72*175

P = 238 torr

The partial pressure of each substance can be found by the multiplication of the molar fraction by the vapor pressure, thus:

Pw = 0.72*175 = 126 torr

Pe = 0.28*400 = 112 torr

To know the number of moles that is vaporized above the solution, we may use the ideal gas law:

PV = nRT

P/n = RT/V

R is the gas constant, T is the temperature and V is the volume, so they are the same for both water and ethanol, thus

Pw/nw = Pe/ne

126/nw = 112/ne

ne = (112/126)*nw

ne = 0.89nw

So, the mole fraction of ethanol is:

ne/(ne + nw) = 0.89nw/(0.89nw + nw) = 0.89/1.89 = 0.47

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