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Oksana_A [137]
3 years ago
9

Solve the equation for x.​

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

x=1

Step-by-step explanation:

multiply both sides by 28 (it is the Least Common Multiple) which would bring your equation to be

7x-2= 4x+1

3x=3

x=1

NemiM [27]3 years ago
4 0

Answer:

x = 28

Step-by-step explanation:

Multiply through by 28 to clear the fractions

28 is the lowest common multiple of 4 and 7

7x - 56 = 4x + 28 ( subtract 4x from both sides )

3x - 56 = 28 ( add 56 to both sides )

3x = 84 ( divide both sides by 3 )

x = 28

You might be interested in
A. In two or more complete sentences, explain how to find the exact value of sec 13pi/6 including quadrant location
Sergio039 [100]

Answer:

A. The exact value of sec(13π/6) = 2√3/3

B. The exact value of cot(7π/4) = -1

Step-by-step explanation:

* Lets study the four quadrants

# First quadrant the measure of all angles is between 0 and π/2

  the measure of any angle is α  

∴ All the angles are acute  

∴ All the trigonometry functions of α are positive

# Second quadrant the measure of all angles is between π/2 and π

  the measure of any angle is π - α

∴ All the angles are obtuse

∴ The value of sin(π - α) only is positive

  sin(π - α) = sin(α)  ⇒ csc(π - α) = cscα

  cos(π - α) = -cos(α)   ⇒ sec(π - α) = -sec(α)

  tan(π - α) = -tan(α)   ⇒ cot(π - α) = -cot(α)

# Third quadrant the measure of all angles is between π and 3π/2

  the measure of any angle is π + α  

∴ All the angles are reflex  

∴ The value of tan(π + α) only is positive

  sin(π + α) = -sin(α)  ⇒ csc(π + α) = -cscα

  cos(π + α) = -cos(α)   ⇒ sec(π + α) = -sec(α)

  tan(π + α) = tan(α)   ⇒ cot(π + α) = cot(α)

# Fourth quadrant the measure of all angles is between 3π/2 and 2π  

  the measure of any angle is 2π - α  

∴ All the angles are reflex

∴ The value of cos(2π - α) only is positive

  sin(2π - α) = -sin(α)  ⇒ csc(2π - α) = -cscα

  cos(2π - α) = cos(α)   ⇒ sec(2π - α) = sec(α)

  tan(2π - α) = -tan(α)   ⇒ cot(2π - α) = -cot(α)

* Now lets solve the problem

A. The measure of the angle 13π/6 = π/6 + 2π

- The means the terminal of the angle made a complete turn (2π) + π/6

∴ The angle of measure 13π/6 lies in the first quadrant

∴ sec(13π/6) = sec(π/6)

∵ sec(x) = 1/cos(x)

∵ cos(π/6) = √3/2

∴ sec(π/6) = 2/√3 ⇒ multiply up and down by √3

∴ sec(π/6) = 2/√3 × √3/√3 = 2√3/3

* The exact value of sec(13π/6) = 2√3/3

B. The measure of the angle 7π/4 = 2π - π/4

- The means the terminal of the angle lies in the fourth quadrant

∴ The angle of measure 7π/4 lies in the fourth quadrant

- In the fourth quadrant cos only is positive

∴ cot(2π - α) = -cot(α)

∴ cot(7π/4) = -cot(π/4)

∵ cot(x) = 1/tan(x)

∵ tan(π/4) = 1

∴ cot(π/4) = 1

∴ cot(7π/4) = -1

* The exact value of cot(7π/4) = -1

5 0
4 years ago
Carys is checking her tax bill for the last year .the tax rates were as follows: no tax on the first 11000 of earnings .earnings
faust18 [17]

Answer:

$7,440.

Step-by-step explanation:

We have been given the tax rates as follows:

$0-$11,000 = No tax.

$11,000-$43,000 = 20%.

$43,000-$150,000 = 40%.

Earnings over $150,000 = 45%.

Since last year Carys earned $45,600, so we will have to find the tax paid by her for 11,000-43,000 at rate of 20%, then the tax for amount over 43,000 at the rate of 40%.

\text{The amount of tax paid by Carys for 11000-43000}=\frac{20}{100}\times (43,000-11,000)  

\text{The amount of tax paid by Carys for 11000-43000}=0.20\times (32,000)

\text{The amount of tax paid by Carys for 11000-43000}=6400

\text{The amount of tax paid by Carys for the amount over 43000}=\frac{40}{100}\times (45,600-43,000)

\text{The amount of tax paid by Carys for the amount over 43000}=0.40\times (2600)

\text{The amount of tax paid by Carys for the amount over 43000}=1040

\text{The total amount of tax paid by Carys}=6400+1040

\text{The total amount of tax paid by Carys}=7440

Therefore, Carys paid an amount of $7,440 in tax.

6 0
3 years ago
Read 2 more answers
There are 180 cars in the parking lot 30% are red cars how many red cards are there
Yuri [45]
There are 54 red cars
7 0
2 years ago
Read 2 more answers
What is the value of StartFraction negative 8 (17 minus 12) over Negative 2 (8 minus (negative 2)) EndFraction?
lana [24]
-2
8(17-12)/ -2(8+2).
A negative and a negative equals a plus
8(5) / -2(10)
40 / -20
= -2
6 0
3 years ago
Read 2 more answers
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
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