Solve the equation for x.

Mathematics

2 answers:

devlian [24]3 years ago

7 0

Answer:

x=1

Step-by-step explanation:

multiply both sides by 28 (it is the Least Common Multiple) which would bring your equation to be

7x-2= 4x+1

3x=3

x=1

NemiM [27]3 years ago

4 0

Answer:

x = 28

Step-by-step explanation:

Multiply through by 28 to clear the fractions

28 is the lowest common multiple of 4 and 7

7x - 56 = 4x + 28 ( subtract 4x from both sides )

3x - 56 = 28 ( add 56 to both sides )

3x = 84 ( divide both sides by 3 )

x = 28

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Read 2 more answers

Solve -3x² + 30x - 90 = 0.<br> A.) x=5±2i√5<br> B.) x=5±i√5<br> C.) x=10±2i√5<br> D.) x= 10±i√5

AnnyKZ [126]

Answer: B.) x=5±i√5.

Step-by-step explanation:

$\displaystyle\\-3x^2+30x-90=0\\-3*x^2-((-3)*10)*x+((-3)*30)=0\\-3*(x^2-10x+30=0\\Divide\ the\ equation\ by\ -3:\\$

$\displaystyle\\x^2-10x+30=0\\a=1\ \ \ \ b=-10\ \ \ \ c=30\\D=b^2-4ac\\D=(-10)^2-4*1*30\\D=100-120\\D=-20\\\sqrt{D}=\sqrt{-20} \\\sqrt{D}=\sqrt{-1*4*5} \\ \sqrt{D}=2*\sqrt{-1*5}\\ \sqrt{-1}=i\\ \sqrt{D}=2i\sqrt{5} \\ x_{1,2}=\frac{-bб\sqrt{D} }{2} \\x_{1,2}=\frac{-(-10)б2i\sqrt{5} }{2}\\ x_{1,2}=\frac{10б2i\sqrt{5} }{2}\\ x_{1,2}=5бi\sqrt{5}.$