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Llana [10]
3 years ago
9

Helploopopoooo messee

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
The answer is sodium sulfate
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An organic compound absorbs strongly in the IR at 1687 cm1. Its 'H NMR spectrum consists of two signals, a singlet at 2.1 ppm an
tatuchka [14]

This question does not contain the structures of the molecules. The structures in Daylight SMILES format are:

I. C1=CC=CC=C1C(=O)C

II. C1=CC=CC=C1CC=O

III. C1=CC(C)=CC=C1C=O

IV. C1=CC=CC=C1CCC

V. C1=CC=CC=C1C(C)C

The structures are also attached

Answer:

The structure of compound IV is consistent with the information obtained analysis

Proposed structures for the ions with m/z values of 120, 105,77 and 43 are (also attached):

C1=CC=CC=C1C(=[OH0+])C |^1:7|

C1C([CH0+]=O)=CC=CC=1

C1[CH0+]=CC=CC=1

C(#[OH0+])C

respectively

Explanation:

The IR peak at 1687 cm⁻¹ is indicative of an α unsaturated carbonyl carbon. While the 1H NMR singlet is of the methyl group next to carbonyl and the multiplet near 7.1 ppm is a characteristic peak of benzene. This data shows points towards structure I.

Mass spectrum peak at 120 m/z is of molecular ion peak. In the case of carbonyl-containing molecule, this peak is observable. The signal at 105 shows the loss of a methyl group next to the carbonyl. m/z value of 77 is the characteristic cationic peak of benzene, while the peak at 43 infers the formation of acylium ion (RCO+) due to α-cleavage. All this data agrees with the structure of acetophenone (Structure 1)

6 0
4 years ago
Equal volumes of H2 and O2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi
Sonbull [250]

Answer: Oxygen

Explanation:

2H_2+O_2\rightarrow 2H_2O

As seen from the balanced equation:

2 moles of hydrogen combine with 1 mole of oxygen or 1 mole of hydrogen combine with 1/2 mole of oxygen.

According to Avogadro's law, equal volumes of gases contain equal number of molecules and hence equal number of moles.

Thus if x moles of both gases are present, x moles of hydrogen will combine with \frac{x}{2} moles of oxygen and  x-\frac{x}{2}=\frac{x}{2} moles of oxygen will be left used and will be in excess.

7 0
3 years ago
Natural disasters can cause both immediate and long-term issues. For example, flooding is an immediate threat with dangerous hig
GalinKa [24]

Answer:

. B. The boxes must minimize thermal energy transfer to prevent thermal energy from transferring into the boxes.

Explanation:

If a box is to remain cool, energy transfer into the box must be minimized and energy transfer out of the box must be maximized.

This implies that only a minimal amount of thermal energy can transfer into the box while the box looses heat rapidly. If a box is this designed, it is likely to remain cool.

3 0
3 years ago
How is the number 3.91 x 10-4 expressed in regular numbers?
Semenov [28]

To convert a number without the use of the expression 10^-4 you would have to treat it like an integer line for instance on an integer line the negative is to the left and the positive number is to the right so 3.91*10^-4 means that the decimal would have to move 4 places to the left so the answer would be .000391 instead of 3.91*10^-4.


I hope this helps you :)

3 0
3 years ago
Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A
Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k[NO_3][CO]

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)

The intermediate reaction of the mechanism follows:

Step 1:  2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}

Step 2:  NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[NO_3][CO]

Hence, the rate law for the reaction is written above.

5 0
4 years ago
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