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3 years ago

Please help me :( I’ll give brainlist

Chemistry

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

76. 726

Explanation:

0.454 × 169

Hope this helps

LiRa [457]3 years ago

4 0

Answer:

76.726 kg

Explanation:

1 lb = 0.454 kg

169 lb

= 169 x 0.454

= 76.726 kg

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A man swims for 30 minutes at a speed of 109m/min how far does he swim

allochka39001 [22]

Answer:

3270m

Explanation:

1 minute= 109m

30 minutes= 109 × 30 = 3270m

(whatever you do on one side you have to do to the other)

hope this helps :)

5 0

3 years ago

Someone please answer the question attached.

nikdorinn [45]

Answer:

Option ( 1 )

Explanation:

This atom has a cub close pack structure, and therefore - the number of edge center present in X atoms = 4,

Number of unit cells present in X atoms = 6

____________________________________________________

Now the 6th coordination number of X atom = 6 * 4 = 24,

So respectively, the 3rd coordination number of X = 8 -

And thus the ratio between the 6th coordination number and the 3rd coordination number = 24 / 8 = 3,

Option ( 1 )

Hope that helps!

5 0

3 years ago

When an aqueous solution of magnesium nitrate is mixed with an aqueous solution of potassium carbonat?

vodka [1.7K]

Chemical eqn
Mg(NO3)2 + K2CO3 ----> MgCO3 + 2KNO3

4 0

3 years ago

Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard thermodynamic data at 298K, calculate the entropy change f

Ulleksa [173]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cl_2(g))})+(2\times \Delta S^o_{(H_2O(g))})]-[(4\times \Delta S^o_{(HCl(g))})+(1\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(O_2(g))}=205.14J/K.mol\\\Delta So_{(HCl(g))}=186.91J/K.mol\\\Delta S^o_{(Cl_2(g))}=223.07J/K.mol\\\Delta S^o_{(H_2O(g))}=188.82J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (223.07))+(2\times (188.82))]-[(4\times (186.91))+(1\times (205.14))]\\\\\Delta S^o_{rxn}=-129J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-129) J/K = 129 J/K

We are given:

Moles of HCl gas reacted = 2.27 moles

By Stoichiometry of the reaction:

When 4 mole of HCl gas is reacted, the entropy change of the surrounding will be 129 J/K

So, when 2.27 moles of HCl gas is reacted, the entropy change of the surrounding will be = $\frac{129}{4}\times 2.27=73.21J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

3 0

3 years ago

What would the mass of 7 red apples be in kilograms?

Bogdan [553]

Answer:

I think it would be at 0.7 kg mass of the sun

8 0

3 years ago