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Yuri [45]
3 years ago
11

Please help me :( I’ll give brainlist

Chemistry
2 answers:
luda_lava [24]3 years ago
7 0

Answer:

76. 726

Explanation:

0.454 × 169

Hope this helps

LiRa [457]3 years ago
4 0

Answer:

76.726 kg

Explanation:

1 lb = 0.454 kg

169 lb

= 169 x 0.454

= 76.726 kg

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Consider a mixture of NaCl and NaNO3 that is 31.8% Na by mass. Calculate the percentage by mass of NaCl in the mixture.
lutik1710 [3]

<u>Answer:</u> The percentage by mass of NaCl in the mixture is 38.5 %

<u>Explanation:</u>

To calculate the mass percentage of element in compound, we use the equation:

\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      .......(1)

  • <u>For NaCl:</u>

Mass of sodium element = 23 g

Mass of NaCl = 58.5 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{58.5g}\times 100=39.32\%

Mass fraction of sodium metal in NaCl = 0.3932

  • <u>For NaNO_3 :</u>

Mass of sodium element = 23 g

Mass of NaNO_3 = 85 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{85g}\times 100=27.1\%

Mass fraction of sodium metal in sodium nitrate = 0.271

Let us assume the mass fraction of NaCl in the mixture is 'x'

So, the mass fraction of NaNO_3 in the mixture will be '(1-x)'

We are given:

Percent by mass of Na in the mixture = 31.8 %

Mass fraction of Na in the mixture = 0.318

Evaluating the mass fraction of NaCl in the mixture:

[(x\times 0.3932)+((1-x)\times 0.271)]=0.318

x = 0.385

Percent by mass of NaCl in the mixture will be = (0.385\times 100)=38.5\%

Hence, the percentage by mass of NaCl in the mixture is 38.5 %

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