Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
X^2 + 50
√x^2+ √50
x + 5√2
5√2 = ~7.07106
x + 7.07106
x = -7.07106
hope this helps
Is there a picture of the answers to go with this ?
Step-by-step explanation:
Using Binomial Expansion,
(x + y)³
= 3C0 * x³ + 3C1 * x²y + 3C2 * xy² + 3C3 * y³.
Therefore the coefficient of xy² is 3C2 = 3.
Simplified: -6m-6
Factored: 6(m+1)
