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Salsk061 [2.6K]

3 years ago

8

Suppose you place a ball in the middle of a wagon, and then accelerate the wagon forward. Describe the motion of the ball relati

ve to the ground.

1 answer:

Alborosie3 years ago

5 0

Answer:

It will have more speed/more acceleration than or the ground.

Explanation:

It will lean twords the side that moves and for ex if the wagon has a level to pull a gap down the ball will go forward

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Which of the following ions/atoms has the smallest radius?

Anna11 [10]

Answer:

B I believe im sorry if it's not right

8 0

3 years ago

A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.

Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0

3 years ago

we know from Newton’s 2nd Law of Motion that the force on an object is equal to the mass of the object times the acceleration of

ANTONII [103]

The acceleration of the ball was 0.6 m·s⁻².

<em>F = ma</em>

<em>a = F</em>/<em>m</em> = 5 N/9 kg × (1 kg·m·s⁻²/1 N) = 0.6 m·s⁻²

5 0

3 years ago

The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea

Mariana [72]

Answer:

$\frac{1}{8}$

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

$\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}$

We can construct a table.

<u>No of half-lives</u> <u>Fraction remaining</u>

1 $\frac{1}{2}$

2 $\frac{1}{4}$

3 $\frac{1}{8}$

The general formula is

$\text{Fraction remaining} = \frac{1}{2^{n}}$

where <em>n</em> = the number of half-lives.

Thus, $\frac{1}{8}$ of the original carbon remains after 17 190 y.

8 0

3 years ago

What mass of carbon dioxide can be produced from 4 moles of sodium bicarbonate according to the following unbalanced reaction,

KonstantinChe [14]

The answer is on the paper

6 0

3 years ago