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AleksandrR [38]
1 year ago
6

A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0

mm Hg?
Chemistry
1 answer:
masha68 [24]1 year ago
5 0

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at  273.15 K

P1V1/T1  = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K     = 1.788 C

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Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

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Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

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Step 3:

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