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maxonik [38]
3 years ago
5

At midnight, the temperature in a city was 5 degrees Celsius. The temperature was dropping at a steady rate of 2 degrees Celsius

per hour. Write an inequality that represents h, the number of hours past midnight, when the temperature was colder than -7 degrees Celsius. *
Mathematics
1 answer:
fredd [130]3 years ago
3 0

Answer:

     5- 2h = -7 ?

Step-by-step explanation:Im not really sure if im right :(

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Question 1<br> If f(x) = (x-1), what is f(-4.2)?
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-5.2

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What is the surface of the solid ​
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3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
4 years ago
2(-3a+5)=-4(a+4)<br>helps plzs!!!!.....​
Nana76 [90]
-6a+10=-4a-16
-6a+26=-4a
26=2a
A=13
8 0
3 years ago
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