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3 years ago

Calcule el porcentaje de soluto (%vv) en una disolución preparada con 45,2 mL de ácido nítrico en 205 mL de agua.

Chemistry

1 answer:

ryzh [129]3 years ago

5 0

Answer:

18.1% V/V

Explanation:

El porcentaje volumen/volumen (%v/v) es una unidad de concentración en química definida como la relación entre volumen de soluto y volumen total de la solución (En las mismas unidades ambos volúmenes) por cien. La fórmula es:

% V/V = Volumen soluto / Volumen solución × 100

Analizando el problema, el soluto es ácido nítrico (Menor cantidad) y el solvente es el agua.

Recordando, el volumen de la solución es igual al volumen del soluto + el volumen del solvente. Así:

% V/V = 45.2mL soluto / (45.2mL + 205mL) × 100 =

<em>18.1% V/V</em> es la concentración de la solución.

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A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?

Komok [63]

Answer:

Ok:

Explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.

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2 years ago

For each of the following reactions, identify the missing reactant(s) or products(s) and then balance the resulting equation. No

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Answer:

A. The reactants are= Li and O2

The balanced equation is:

4Li + O2 —> 2Li2O

B. The products are: MgCl2 and O2

The balanced equation is:

Mg(ClO3)2 —> MgCl2 + 3O2

C. The products are: Ca(NO3)2 and H2O

The balanced equation is:

2HNO3 + Ca(OH)2 —> Ca(NO3)2 +

2H2O

D. The products are: CO2 and H2O

The balanced equation is:

C5H12 + 8O2 —> 5CO2 + 6H2O

Explanation:

A. ____ —> Li2O

The reactants are Li and O2. Thus the equation is given below:

Li + O2 —> Li2O

Thus the equation is balanced as follow:

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Li2O as shown below:

Li + O2 —> 2Li2O

Now, we have 4 atoms of Li on the right side and 1 atom on the left. It can be balance by putting 4 in front of Li as shown below:

4Li + O2 —> 2Li2O

Now the equation is balanced

B. Mg(ClO3)2 —> __

The products are MgCl2 and O2

The equation is given below:

Mg(ClO3)2 —> MgCl2 + O2

The equation can be balance as follow:

There are 6 atoms of O on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:

Mg(ClO3)2 —> MgCl2 + 3O2

Now the equation is balanced

C. HNO3 + Ca(OH)2 —>___

The products are: Ca(NO3)2 and H2O

The equation is given below:

HNO3 + Ca(OH)2 —> Ca(NO3)2 + H2O

The equation is balanced as follow:

There are 2 atoms of NO3 on the right side and 1 atom on the left. It can be balance by putting 2 in front of HNO3 as shown below:

2HNO3 + Ca(OH)2 —> Ca(NO3)2 + H2O

There are a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

2HNO3 + Ca(OH)2 —> Ca(NO3)2 + 2H2O

Now the equation is balanced

D. C5H12 + O2 —>__

The products are: CO2 and H2O

The equation is given below:

C5H12 + O2 —> CO2 + H2O

The equation can be balance as follow:

There are 5 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 5 in front of CO2 as shown below:

C5H12 + O2 —> 5CO2 + H2O

There are 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

C5H12 + O2 —> 5CO2 + 6H2O

Now, there are a total of 16 atoms of O on the right side and 2 atoms on the left. It can be balance by putting 8 in front of O2 as shown below:

C5H12 + 8O2 —> 5CO2 + 6H2O

Now we can see that the equation is balanced.

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3 years ago

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Answer:

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Explanation:

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2 years ago

Acids or bases can be tested by chemical_________

DedPeter [7]

Answer:

acids or bases can be tested

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2 years ago

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Silver was precipitated and collected by filtration. The experiment yielded .077g of silver after dying. The predicted yield was

PSYCHO15rus [73]

Answer:

Precentage error = 7.23%

Explanation:

The precentage error formula is the useful method for determining precision of your experimental result

It can be calculated using :

$percent\ error = |\frac{experimental\ value-predicted\ value} {predicted\ value}|\times 100$

$percent\ error = |\frac{0.077\ -0.083} {0.083}|\times 100$

So we get percentage error = 7.23%

Precision means how close the experimental value to the true value or theoretical value

If percentage error is large it means experimental results are deviated and there is need to check mistakes,imprecision in the experiment

If the percentage error is zero it means the experiment is perfectly done without inaccuracy

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3 years ago