Answer:- Actual molarity of the original sulfuric acid solution is 17.0M.
Solution:- Barium chloride reacts with sulfuric acid to make a precipitate of barium sulfate. The balanced equation is written as:
From this equation there is 1:1 mol ratio between barium sulfate and sulfuric acid. So, if excess of barium chloride is added to sulfuric acid then the moles of sulfuric acid would be equivalent to the moles of barium sulfate. Moles of barium sulfate could be calculated from the mass of it's dry precipitate.
Molar mass of barium sulfate is 233.4 grams per mol. The calculations for the moles of sulfuric acid are given below:
= 
From given information, 10.00 mL of final acid solution were taken to react with excess of barium chloride. It means 0.00170 moles of sulfuric acid are present in 10.0 mL of final acid solution. We could calculate the actual molarity of the final solution from here as:
10.0 mL = 0.0100 L
= 0.170M
Now we would use the dilution equation to calculate the actual molarity of the original sulfuric acid solution. The molarity equation is:
From given information, 10.0 mL of original acid solution were taken in a 100 mL flask and water was added up to the mark. It means the 10 fold dilution is done. 10 fold dilution means the molarity becomes one tenth of it's original value. Let's do the calculations in reverse way as we have calculated the molarity of the final solution.
let's say the molarity after first dilution is Y. the volume is taken as 10.0 mL. Final volume is 100 mL and the molarity is 0.170M. Let's plug in the values in the equation:
Y(10.0mL) = 0.170M(100mL)
![Y=\frac{0.170M*100mL}{10.0mL}Y = 1.70MLet's do the similar calculations to find out the actual molarity of the original acid solution. Let's say the molarity of the original acid solution is X. 10.0 mL of it were taken and diluted to 100 mL on adding water. The molarity is 1.70M as is calculated in the above step. Let's plug in the values in the molarity equation again to solve it for X as:X(10.0mL) = 1.70M(100mL)[tex]X=\frac{1.70M*100mL}{10.0mL}](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B0.170M%2A100mL%7D%7B10.0mL%7D%3C%2Fp%3E%3Cp%3EY%20%3D%201.70M%3C%2Fp%3E%3Cp%3ELet%27s%20do%20the%20similar%20calculations%20to%20find%20out%20the%20actual%20molarity%20of%20the%20original%20acid%20solution.%20Let%27s%20say%20the%20molarity%20of%20the%20original%20acid%20solution%20is%20X.%2010.0%20mL%20of%20it%20were%20taken%20and%20diluted%20to%20100%20mL%20on%20adding%20water.%20The%20molarity%20is%201.70M%20as%20is%20calculated%20in%20the%20above%20step.%20Let%27s%20plug%20in%20the%20values%20in%20the%20molarity%20equation%20again%20to%20solve%20it%20for%20X%20as%3A%3C%2Fp%3E%3Cp%3EX%2810.0mL%29%20%3D%201.70M%28100mL%29%3C%2Fp%3E%3Cp%3E%5Btex%5DX%3D%5Cfrac%7B1.70M%2A100mL%7D%7B10.0mL%7D)
X = 17.0M
Hence, the actual molarity of sulfuric acid solution is 17.0M.
Answer:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, the rate is given as:
![rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}](https://tex.z-dn.net/?f=rate%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7B%5CDelta%20%5BHBr%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BBr_2%5D%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7B%5CDelta%20%5BH_2%5D%7D%7B%5CDelta%20t%7D)
It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.
Therefore, the answer is:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Best regards.
The answer is B!!! Statement B is not true!
D, T<span>he total mass of hydrochloric acid used is less than 10 grams.
Conservation of mass, matter cannot be created or destroyed.</span>
An ecosystem is simply a collection of communities of plants, animals, and microbes interacting together and with their physical environments.
<h3>Energy flow in an ecosystem</h3>
Energy enters the ecosystem through a group of living organisms known as the producers. the producers are mainly the green plants that are capable of photosynthesizing.
Photosynthesis converts solar radiation from the sun to chemical energy in green plants. Another group of organisms in the ecosystem, the primary consumers, feed directly on the producers and as such, are able to gain some energy from them.
The secondary consumers obtain their own energy by feeding on primary consumers. Tertiary consumers feed on the secondary consumers for their own energy and the food chain goes on and on.
Only about 10% of the available energy in one trophic level goes to the next trophic level. The rest of the energy is lost as heat to the surroundings. Thus, the producers have the highest energy in the ecosystem while organisms at the top of the food chain have the lowest energy.
More on energy flow in the ecosystem can be found here: brainly.com/question/7582129
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