All categories

3 years ago

Increasing the volume of a given amount of gas at constant temperature causes the pressure to decrease because

2 answers:

7 0

Answer: Increasing the volume of a given amount of gas at constant temperature causes the pressure to decrease because the molecules are more spread apart.

Explanation:

In a container, when volume is increases, the particles get separated from each other.

The intermolecular spacing between the particles increases, which makes the intermolecular interaction between the particles decrease.

When the attraction between the particles decreases, the pressure on the particles also decreases.

Hence, increasing the volume of a given amount of gas at constant temperature causes the pressure to decrease because the molecules are more spread apart.

mestny [16]3 years ago

5 0

Because the molecules are more spread apart.

(gas spread)

You might be interested in

An irreversible change would be?

klemol [59]

Answer:

A. Chipping ice to flakes

Explanation:

You can't reverse the ice becoming flakes. They will stay like that until they melt

8 0

2 years ago

Assume an object A with a mass of 66.789 g and a volume of 10.1 mL. what is its density?

docker41 [41]

Answer: 6.61

Explanation:

5 0

3 years ago

Find percent yield:

saveliy_v [14]

Answer: The percent yield of the reaction is 91.8 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $B_5H_9$ :

Given mass of $B_5H_9$ = 4.0 g

Molar mass of $B_5H_9$ = 63.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol$

For oxygen gas:

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol$

The chemical equation for the reaction of $B_5H_9$ and oxygen gas follows:

$2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O$

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of $B_2H_5$

So, 0.3125 moles of oxygen gas will react with = $\frac{2}{12}\times 0.3125=0.052mol$ of $B_2H_5$

As, given amount of $B_2H_5$ is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of $B_2O_3$

So, 0.3125 moles of oxygen gas will produce = $\frac{5}{12}\times 0.3125=0.130moles$ of water

Now, calculating the mass of $B_2O_3$ from equation 1, we get:

Molar mass of $B_2O_3$ = 69.93 g/mol

Moles of $B_2O_3$ = 0.130 moles

Putting values in equation 1, we get:

$0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g$

To calculate the percentage yield of $B_2O_3$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $B_2O_3$ = 8.32 g

Theoretical yield of $B_2O_3$ = 9.052 g

Putting values in above equation, we get:

$\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%$

Hence, the percent yield of the reaction is 91.8 %

6 0

3 years ago

Who was the first person to discover the existence of electrons

k0ka [10]

Electron was discovered by J. J. Thomson in 1897 when he was studying the properties of cathode ray.

4 0

3 years ago

Read 2 more answers

What charge would an arsenic, As, ion have? Explain.

leva [86]

Answer:

Arsenic (As) anion has -‐3 charge, but also forms cations with +3 or +5 charge.

Explanation:

5 0

3 years ago