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Cerrena [4.2K]
3 years ago
8

Carbon and silicon are tetravalent but ge sn pb show di valency. Why

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

<u>Answer:</u>

Carbon and silicon both are tetravalent elements as compared to germanium, tin, and lead which are divalent.

That's because Ge, tin, and Pb show inert pair effect and has a greater nuclear effective charge on the 's' electrons due to poor shielding effect.  .That's why these elements are not able to share their valence electrons while carbon and silicon does and show "catenation" which is the ability to form long chain molecules.

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One property of metals is that they are: insulators brittle malleable none of these are properties of metals
wel
Metals are insulators and malleable. Hope this helps even though I'm late :)
6 0
3 years ago
What volume of 0.08892 M HNO3 is required to react completetly with 0.2352 g of potassium hydrogen phosphate?
galina1969 [7]

Answer:

0.0303 Liters

Explanation:

Given:

Mass of the potassium hydrogen phosphate = 0.2352

Molarity of the HNO₃ Solution = 0.08892 M

Now,

From the reaction it can be observed that 1 mol of potassium hydrogen phosphate reacts with 2 mol of HNO₃

The number of moles of 0.2352 g of potassium hydrogen phosphate

= Mass / Molar mass

also,

Molar mass of potassium hydrogen phosphate

= 2 × (39.09) + 1 + 30.97 + 4 × 16 = 174.15 g / mol

Number of moles = 0.2352 / 174.15 = 0.00135 moles

thus,

The number of moles of HNO₃ required for  0.00135 moles

= 2 ×  0.00135 mol of HNO₃

= 0.0027 mol of HNO₃

Now,

Molarity = Number of Moles / Volume

thus,

for 0.0027 mol of HNO₃, we have

0.08892 = 0.0027 / Volume

or

Volume =  0.0303 Liters

8 0
3 years ago
Read 2 more answers
What is the percent composition HCN?
kupik [55]

Answer:

see calculations in explanation

Explanation:

percent = part/total x 100%

part = ∑ atomic mass of element

  • hydrogen = 1.008 amu (atomic mass units)
  • carbon = 12.011 amu
  • nitrogen = 14.007 amu

total = ∑ molecular mass of compound

       = H amu  +  C amu +  Namu

       = 1.008 amu + 12.011 amu + 14.007 amu

       = 27.026 amu

%H = (1.008amu/27.026amu)100% = 3.730%

%C = (12.011amu/27.026amu)100% = 44.442%

%N = (14.007amu/27.026amu)100% = 51.827%

Check results ∑%values = 100%

3.730% + 44.442% + 51.827% = 99.999% ≅ 100%

7 0
3 years ago
Calculate the p value of each ion indicated:
Nataliya [291]
27/208  = normality

12 x 10^-2 approx  = normality

nw Ka = 14.3 x 10^-3

pKa = 3 - log 14

now, after getting the pKa put it in formula  :
pH = pKa + log concn of ion/concn of salt and you'll get it

hope this helps
8 0
3 years ago
Consider the electrolysis of aqueous agno3. Refer to the table of standard reduction potentials as needed. What should form at t
Valentin [98]

Answer:

Ag+

Explanation:

anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)

8 0
3 years ago
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