Answer:
D/CH3COOH
Explanation:
CH3COOH is a weak acid, it partially dissociates into its ions in an aqueous solution.
<h3>
Answer:</h3>
318.405 g
<h3>
Explanation:</h3>
We are given;
- Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
- Molarity of the solution to be prepared as 2.00 M
We are required to determine the mass of K₃PO₄ to be measured.
<h3>Step 1: Determine the number of moles of K₃PO₄</h3>
Molarity = Moles ÷ Volume
Rearranging the formula;
Number of moles = Molarity × Volume
Therefore;
Moles of K₃PO₄ = 2.00 M × 0.75 L
= 1.5 moles
<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>
Mass = Number of moles × Molar mass
Molar mass of K₃PO₄ = 212.27 g/mol
Therefore;
Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol
= 318.405 g
Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g
Answer:
there is 1 leftover because your adding to 1... I think
Explanation:
Answer:
The nucleus of an atom consists of Protons and Neutrons.-A.
