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RSB [31]
3 years ago
6

what mass of grams of hydrogen sulfide will be required to participate 15 g of copper sulphide from a copper (ii) traoxosulphate

(vi) solution​
Chemistry
1 answer:
cestrela7 [59]3 years ago
7 0
Characteristics of a Precipitate:
A precipitate is characterized by the following properties:

Appears as a solid species.
Settled down at the bottom of the reaction pot.
Insoluble in the corresponding solvent.
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The equilibrium constant, Kc, for the following reaction is 56.0 at 278 K. 2CH2Cl2(g) CH4(g) + CCl4(g) When a sufficiently large
BabaBlast [244]

Answer:

  • <u>21.5 M</u>

Explanation:

<u>1) Equilibrium equation (given):</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

<u>2) Write the concentration changes when some concentration, A, of CH₂Cl₂ (g) sample is introduced into an evacuated (empty) vessel:</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

           A - x                 x              x

<u>3) Replace x with the known (found) equilibrium concentraion of CCl₄ (g) of 0.348 M</u>

  • 2CH₂Cl₂ (g)   ⇄ CH₄ (g) + CCl₄ (g)

          A - 0.3485       0.348       0.348

<u>4) Write the equilibrium constant equation, replace the known values and solve for the unknown (A):</u>

  • Kc = [ CH₄ (g) ] [ CCl₄ (g) ] / [ CH₂Cl₂ (g) ]²

  • 56.0 = 0.348² / A²

  • A² = 56.0 / 0.348² = 462.

  • A = 21.5 M ← answer

7 0
3 years ago
What have six valence electrons
irina1246 [14]

Any element in group 18 has eight valence electrons (except for helium, which has a total of just two electrons). Examples include neon (Ne), argon (Ar), and krypton (Kr). Oxygen, like all the other elements in group 16, has six valence electrons.

6 0
3 years ago
Read 2 more answers
What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?
Phantasy [73]

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

8 0
3 years ago
2(x-1 ➗ x+3)-7(x+3 ➗ x-1)=5​
NeTakaya
I attached a photo of my work below. Please tell me if I got it wrong; hope you got a good score on your assignment! ^v^

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3 years ago
On a hiking trip, you see a large tree root has grown into the cracks of a rock and caused it to break apart. This is an example
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Hydrologic Weathering I think
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