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koban [17]
3 years ago
8

Dan rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 3. Answer pls its my

h/w
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

There are 6 * 6 = 36 total outcomes from throwing 2 dice. Of those, there is only 1 that will give you a sum less than 3 (1 + 1) so the answer is 1 / 36.

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Catherine Lewiston is currently earning an annual salary of $36,080 at
Nezavi [6.7K]

Answer:

$212.31

Step-by-step explanation:

divide $36,080 by 52 weeks in a year. you get $693.84 weekly.

divide $47,120 by 52 weeks in a year. you get $906.15 weekly.

then subtract 906.15 from 693.84 and you get 212.31

5 0
3 years ago
1) There are 25 rows of seats on a concert hall: 25 seats are in the 1st row, 28 seats on the 2nd row, 31 seats on
Yuliya22 [10]

Answer:

79

Step-by-step explanation:

6 0
3 years ago
Pls help i want it now​
larisa86 [58]

Answer:

18kg is the correct answer

5 0
2 years ago
1 2/3 X 3/4 what is the awnser with work shown
alex41 [277]
First you would have to turn the mixed number into a improper fraction. to do that you would have to multiply the denominator by the 1 (which is the whole number) to get 3*1=3 then you would have to add the numerator to get 3+2=5. now you have an improper fraction which is now 5/3. you always keep the denominator the same. next you have to multiply the two fractions you now have. which is 5 over 3 and 3 over 4 . all you have to do is multiply across to get 5*3=15 on the top and 3*4=12 on the bottom. so your new fraction you have is 15/12. that's an improper fraction so you would have to divide 12 by 15. you know 12 goes into 15 one time with a remainder of 3. so now you have 1 3/12 as your answer. but your not done yet. now you have to simplify your answer by dividing the numerator and denominator by 3 to get 3/3=1 and 12/3=4, you final answer should be 1 1/4 .
6 0
3 years ago
Perform the modular arithmetic. (7 · 15) (mod 4)
Reika [66]

We could do it by first writing

7\cdot15=(4+3)\cdot(4+11)=4^2+14\cdot4+33

so that

7\cdot15\equiv4^2+14\cdot4+33\equiv33\pmod4

and since 33=32+1=8\cdot4+1, we have

7\cdot15\equiv33\equiv1\pmod4

# # #

Alternatively, we can just compute the product and take it mod 4:

7\cdot15=105=104+1=26\cdot4+1

and so we get the same result of 1.

4 0
3 years ago
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