Answer:
698.46 Hz
Step-by-step explanation:
A note an octave higher than another note is double the amount of frequency.
In this example, the note is 349.23 Hz. Doubled, this is 698.46 Hz. Therefore, the final answer is the first option, 698.46 Hz
m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
H= g + 15
15. 30
30. 45
35 50
45 60
Hope this helps :)
A) if 3.5 fudge is 18.20 then 3.5 times 2 is 7 then 18.20 times 2 is 36.40 which is how much it will cost.
B) i believe it would be 5.20x because it’s always changing at that rate
Answer: X=35
Step-by-step explanation:
