Answer:
Option B.
Step-by-step explanation:
Let as consider the given equation:
It can be written as
On comparing both sides, we get
Multiply both sides by 5.
Divide both sides by 2.
Therefore, the correct option is B.
Answer:
B
Step-by-step explanation:
There is a vertical asymptote at x=3. It is not defined and therefore not included in the domain.
All other numbers are included in the domain.
Answer:
which class are you in? because it is soo difficult!!!
Answer:
0.8
Step-by-step explanation:
i just did it
![1\frac23-\frac34](https://tex.z-dn.net/?f=1%5Cfrac23-%5Cfrac34)
Write 1 2/3 as an improper fraction...
1 = 3/3. Plus the 2/3 makes 5/3.
![\frac53-\frac34](https://tex.z-dn.net/?f=%5Cfrac53-%5Cfrac34)
To add/subtract fractions, they need the same denominator. (bottom number)
We can change the denominator by multiplying the top and bottom of a fraction by the same number. (it will stay equal, like 1/2 and 2/4)
Let's change 5/3 and 3/4 to a denominator of 12.
5/3 = 20/12 (bottom multiplies by 4, so does the top)
3/4 = 9/12 (bottom multiplies by 3, so does the top)
![\frac{20}{12}-\frac9{12}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B12%7D-%5Cfrac9%7B12%7D)
Now we just subtract the 20 minus 9 twelfths. (the twelfths act as a sort of unit)