Answer:
0.30M HOAc
Explanation:
Given 250.0ml (0.96M HOAc) => 800ml(??M HOAc)
Use the dilution equation...
(Molarity x Volume)concentrated soln = (Molarity x Volume)dilute soln
(0.96M)(250.0ml) = (Molarity diluted soln)(800ml)
Molarity diluted soln = (0.96M)(250.0ml)/(800ml) = 0.30M HOAc
The valence electrons of both fluorine and
carbon are found at about the same distance
from their respective nuclei but the greater
positive charge of the fluorine nucleus attracts
its valence electrons more strongly.
Answer : The amount of heat released, -35057 J
Solution :
Process involved in the calculation of heat released :
![(1):H_2O(g)(100^oC)\rightarrow H_2O(l)(100^oC)\\\\(2):H_2O(l)(100^oC)\rightarrow H_2O(l)(25^oC)](https://tex.z-dn.net/?f=%281%29%3AH_2O%28g%29%28100%5EoC%29%5Crightarrow%20H_2O%28l%29%28100%5EoC%29%5C%5C%5C%5C%282%29%3AH_2O%28l%29%28100%5EoC%29%5Crightarrow%20H_2O%28l%29%2825%5EoC%29)
Now we have to calculate the amount of heat released.
where,
Q = amount of heat released = ?
m = mass of water = 18 g
= specific heat of liquid water =
= enthalpy change for condensation = -40700 J/mole
Now put all the given values in the above expression, we get
![Q=-35057J](https://tex.z-dn.net/?f=Q%3D-35057J)
Therefore, the amount of heat released, -35057 J
Answer:
ethanoic acid
Explanation:
For two carbon atom used eth
For saturated hydrocarbon or C-C single bond used ane means name is eth +ane = ethane
For –COOH used -oic acidby Replace the –e ending so the name becomes ethanoic acid
Complete question
The complete question is shown on the first uploaded image
Answer:
The value is ![C = 0.02009 \ M](https://tex.z-dn.net/?f=C%20%20%3D%20%200.02009%20%5C%20M%20)
Explanation:
From the question we are told that
The mass of NaOH is ![m= 0.8036 g](https://tex.z-dn.net/?f=m%3D%20%200.8036%20g)
In the question DI (stands for de-ionized water )
So the number of moles of NaOH present in the given mass is
Here Z is the molar mass of NaOH with value
So
Given that the volume of the flask is V = 1 L then we can evaluated the concentration as
![C = \frac{n}{V}](https://tex.z-dn.net/?f=C%20%20%3D%20%20%5Cfrac%7Bn%7D%7BV%7D)
=> ![C = \frac{0.02009}{1}](https://tex.z-dn.net/?f=C%20%20%3D%20%20%5Cfrac%7B0.02009%7D%7B1%7D)
=>