When the concentration is expressed in ppm, that means parts per million. It is also equivalent to mg/L. For this problem, we do stoichiometric calculations. We manipulate the units by cancelling like units if they appear in the numerator and denominator side until we come with the amount of solid Ca(OCl)2 needed. The solution is as follows:
40 mg/L * (1 L/1000 mL) * 50 mL * (1 g/1000 mg) * (1 mol OCl⁻/51.452 g) * (1 mol Ca(OCl)₂/ 2 mol OCl⁻) * (142.983 g Ca(OCl)₂/mol) * 0.95 = 2.64×10⁻3 g or 2.64 mg.
Therefore, you would need 2.64 mg of solid Ca(OCl)₂.
Answer:
The answer to your question is 8.1 g of ZnCl₂
Explanation:
Data
mass of ZnCl₂ = ?
mass of Zn = 7.0 g
mass of CuCl₂ = 8 g
Balanced chemical reaction
Zn + CuCl₂ ⇒ ZnCl₂ + Cu
Process
1.- Calculate the molar mass of the reactants
Zn = 65.4 g
CuCl₂ = 63.6 + (35.5 x 2) = 134.6 g
2.- Calculate the limiting reactant
theoretical yield CuCl₂ / Zn = 134.6/65.4 = 2.06
experimental yield CuCl₂ / Zn = 8/7 = 1.1
The limiting reactant is CuCl₂ because the experimental yield was lower than the theoretical yield.
3.- Use proportions to calculate the mass of ZnCl₂
molar mass of ZnCl₂ = 65.4 + (35.5 x 2) = 136.4 g
134.6 g of CuCl₂ ---------------- 136.4 g of ZnCl₂
8 g ---------------- x
x = (8 x 136.4) / 134.6
x = 8.1 g of ZnCl₂
Answer is: 2Zn + O₂ → 2ZnO (2Zn²⁺ + 2O²⁻).
Unbalanced chemical reaction: Zn + O₂ → ZnO.
Zn → Zn²⁺ + 2e⁻ / ×2; 2Zn → 2Zn²⁺ + 4e⁻.
4e⁻ + O₂ → 2O²⁻.
Zinc lost two electrons and became Zn²⁺, molecule of oxygen gain four electrons and become 2O²⁻. Multiply first reaction with two to have same number of electrons and put coefficients in chemical reaction.
To determine the number of phosphorus atoms from a given mass, we need to determine the number of moles of the substance by dividing the molar mass which for in this case is equal to 123.88 g/mol for P4. Then, we multiply Avogadro's number. It <span>represents the number of
units in one mole of any substance. This has the value of 6.022 x 10^23 units /
mole.
mole P4 = 158 kg P4 ( 1000 g / 1 kg ) ( 1 mol / 123.88 g ) = 1275.43 mol P4
# of P4 atoms = 1275.43 mol P4 ( 6.022 x 10^23 atoms P4 / 1 mol P4 ) = 7.68x10^26 atoms P4</span>
Answer:
The most likely outcome is that carrier protein dysfunction will increase the gradient which will lead to disruption of cellular metabolism.
