6: Yes, it is linear. The constant rate of change is

, which you can make

. This simplifies to 15, so the constant rate of change is 15.
7. Yes, a proportional relationship exists because every output value is exactly three times every corresponding input value.
8. Yes, a proportional relationship exists because every output value is exactly

times the corresponding input value.
9. Yes, a proportional relationship exists because every y value is 7.5 times every corresponding x value, and if a line were to be drawn through the points, it would go through the origin (0,0).
93 is 60 percent from the original price.
The discount reduces the original price by 40 percent.
Answer:

Step-by-step explanation:
In leftmost triangle:
opposite side =y
adjacent=a
now, we can use trig formula

now, we can solve for y

In rightmost triangle:
adjacent=b
opposite=y
a+b=15
b=15-a
now, we can use trig formula

now, we can solve for y

now, we can set them equal
and then we can solve for a




now, we can find b


now, we can use trig formula

now, we can find z

we can simplify it
and we get

True ACTUALLY helped? Click on thanks and rate also if u want Mark me as brainliest plz =)