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OLEGan [10]
3 years ago
9

What is 9 1/2 times 5 1/3

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer: 45 1/6

Step-by-step explanation:

9 1/2 × 5 1/3

Multiply the whole numbers= 9 x 5= 45

Then multiply 1/2 by 1/3 = 1/6

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Pls help trig question!!
s2008m [1.1K]

4\sin^2 x - 3 = 3 \sin x\\\\\implies 4\sin^2 x -3 \sin x  -3 =0\\\\\implies 4u^2 -3u -3 =0~~~~~~~~~~~~~~;[\text{Set} ~ \sin x = u]\\\\\implies u = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4\cdot 4 \cdot (-3)}}{2(4)}~~~~~~;[\text{Apply quadratic formula}]\\\\\\\implies u = \dfrac{3\pm\sqrt{57}}8\\\\\implies \sin x = \dfrac{3\pm\sqrt{57}}8~~~~~~;[\text{Substitute back}~ u = \sin x]\\\\\text{Now,}\\\\\sin x = \dfrac{3+\sqrt{57}}8\\\\\text{No solution for}~ x\in \mathbb{R}  ~\text{Since}~ -1\leq \sin x \leq 1\\

\sin x = \dfrac{3 - \sqrt{57}}8\\\\\implies x = n\pi + (-1)^n \sin^{-1} \left(\dfrac{3-\sqrt{57}}8\right)\\\\\\\text{ When n = 1,2 and}~  [0,2\pi]},\\\\\\x= \pi - \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)~ \text{and} ~x =  2\pi + \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)\\\\\text{In decimal,}\\\\x= 3.75~~~~ \text{and}~~~ x =5.68

5 0
2 years ago
Two non-common sides of adjacent supplementary angles form a _____ angle.
mel-nik [20]

Answer:

C. straight

Step-by-step explanation:

 A Linear Pair is two adjacent angles whose non-common sides form opposite rays.

If two angles form a linear pair, the angles are supplementary.

A linear pair forms a straight angle which contains 180º, so you have 2 angles whose measures add to 180, which means they are supplementary.

In the figure given in attachment, AB and BC are two non common sides of ∠ABD and ∠DBC.

∠1 and ∠2 form a linear pair.

The line through points A, B and C is a straight line.

∠1 and ∠2 are supplementary.

Thus two non-common sides of adjacent supplementary angles form a <u>straight</u> angle.

8 0
3 years ago
June 1st = 1223 starting balance
Dima020 [189]

<u>Answer:</u>

The average daily balance for the month of June is 55.16

Solution:

Given, June 1st = 1223 starting balance

June 10th = 615 deposit

So these will add in the account

June 15th = withdrawal of -63

June 22nd = withdrawal of -120

These will be subtracted from the account.

\therefore We have to add the deposits and subtract the withdrawals from the starting balance to obtain the total amount.

So, the total amount deposited in June is (1223 +615-63-120) = 1655

The total days in June is 30. In 30 days, the total deposit is 1655. To calculate the average balance, we have to divide the total amount by the total number of days in the month.

So, in 1 day the deposit is \frac{1655}{30} = 55.16

Hence, the average daily balance for June is = 55.16  

5 0
3 years ago
How do I solve this problem?
lidiya [134]
B = A(1+\frac{i}{n})^{nt}
A = 47900
i = 5% = .05
n = number of compounding periods in a year (1,2,12,365)
t = number of years = 5
4 0
3 years ago
Quadrilateral LMNO is a parallelogram, and LM=24-9 and NO=y-2, find the value of "y" and the length of NO.
Slav-nsk [51]

Answer:

y = 7

NO = 5

Step-by-step explanation:

Let the side of the parallelogram LM and NO given be 2y - 9 and y - 2

Since LMNO is a parallelogram, hence;

LM = NO

2y - 9 = y - 2

2y - y = -2 + 9

y = 7

Since NO = y - 2

NO = 7 - 2

NO = 5

7 0
3 years ago
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