Answer:
C.
Water has a greater density than alcohol.
Explanation:
From the experiment, it can be shown that water has a greater density than the alcohol.
The ice cube is able to float in the water because, the density of the ice is less than the density of the water.
Density of ice < Density of water
So, the ice cube sinks in alcohol because the density of the ice cube is greater than the density of the alcohol.
Density of ice > Density of alcohol
Therefore, we can assume that since the density of ice is greater than density of alcohol, then the density of water is greater than that of the alcohol.
<em>I am going to use first-person pronouns for this drop of water</em>
[ Start ] Liquid
I start out as a drop of water among other drops of water in the ocean. I am currently a liquid as I can change shape easily but I do not float up.
[ Middle ] Gas
The sun feels very hot. From the heat I turn into a gas, specifically water vapor, and float up into the sky.
[ Middle x 2 ] Solid
In the sky I meet up with a lot of my past friends. We form a cloud, and as we grow heavier (the more the merrier) we start to fall down. It is extremely cold now, so we fall down as a solid, also known as hail or snow.
[ End ] Liquid
We hit the ocean again as we fall from the sky. I'm so happy to be back home as a water drop again!
Have a nice day! - <u>Please note this is very simplified</u>
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ
Explanation:
We know that 5.0 g of acetic acid will contain, 5.0g/60 g/mol = 0.083 moles of acetic acid
Now from the reaction equation;
1 mole of acetic acid evolved -871.7 KJ of heat
0.083 moles of acetic acid will evolve 0.083 * -871.7 = -72.35 KJ
For 5.0 g of acetic acid, we can write;
HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ
Answer: 1.5 g/cm^3
Explanation:
Density is mass over volume
42g / 28 cm^3 = 1.5 g/cubic cm
hope this helps
The answer is G. choices b and c only
