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guapka [62]
2 years ago
5

Chemical Reactions/Neutralization Reactions

Chemistry
1 answer:
aliina [53]2 years ago
7 0

Answer:

Hydrochloric acid + sodium hydroxide -> sodium chloride + water

Sulphuric acid + copper hydroxide -> copper sulphate + water

Nitric acid + sodium hydroxide -> sodium nitrate + water

Hydrochloric acid + calcium hydroxide -> calcium chloride + water

Sulphuric acid + potassium hydroxide -> potassium sulphate + water

Hydrochloric acid + lithium hydroxide -> lithium chloride + water

Nitric acid + magnesium hydroxide -> magnesium nitrate + water

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Please select the word from the list that best fits the definition
leonid [27]

Answer:

Systemic Circulation

Explanation:

7 0
3 years ago
Read 2 more answers
An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
3 years ago
Copper is an example of a(n)
expeople1 [14]

copper is not a stone, copper is not a consumption resource, and copper is not renewable, that means that :

d. nonrenewable resource

Explanation:

A nonrenewable source is a source of economic value that cannot be immediately displaced by natural means on a level equal to its destruction. Most fossil fuels, such as oil, natural gas, and coal are estimated nonrenewable resources in that their use is not sustainable because their production takes billions of years.

7 0
4 years ago
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The following are formed as white precipitates in solution except
aniked [119]

Answer:

A. Iron (III) hydroxide

Explanation:

Orange-brown or rust

6 0
3 years ago
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Which statement is correct? A. pKa is not an indicator of acid strength. B. An acid with a small Ka is stronger than an acid wit
Svetradugi [14.3K]

Answer:

D

Explanation:

Since [pKa = - log Ka]....hence..,the larger the Ka value,the stronger the acid is..so this means that the pKa is vice versa

Saying that the smaller the pKa value..the stronger the acid is.

3 0
4 years ago
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