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3 years ago

What reaction type is the followong reaction

Chemistry

1 answer:

Tems11 [23]3 years ago

8 0

Answer:

its the fourth one please mark as brainlest

Explanation:

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Why do liquids flow? A. Liquid particles are wet. B. Liquid particles are smooth. C. Liquid particles are not fixed in place. D.

KonstantinChe [14]

<span>D. Liquid particles are attracted to each other.</span>

7 0

3 years ago

Read 2 more answers

Suppose 2.2 g of hydrochloric acid is mixed with 1.61 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that

kaheart [24]

Answer:

We can produce 2.35 grams sodium chloride

Explanation:

Step 1: Data given

Mass of hydrochloric acid = 2.2 grams

Molar mass of hydrochloric acid (HCl)= 36.46 g/mol

Mass of sodium hydroxide = 1.61 grams

Molar mass of sodium hydroxide = 40.0 g/mol

Step 2: The balanced equation

HCl + NaOH → NaCl + H2O

Step 3: Calculate moles HCl

Moles HCl = mass HCl / molar mass HCl

Moles HCl = 2.2 grams / 36.46 g/mol

Moles HCl = 0.0603 moles

Step 4: Calculate moles NaOH

Moles NaOH = 1.61 grams / 40.0 g/mol

Moles NaOH = 0.0403 moles

Step 5: Calculate the limiting reactant

NaOH is the limiting reactant. It will completely be consumed (0.0403 moles). HCl is in excess. There will react 0.04025 moles. There will remain 0.0603 -0.0403 = 0.0200 moles

Step 6: Calculate moles sodium chloride

For 1 mol HCl we need 1 mol NaOH to produce 1 mol NaCl and 1 mol H2O

For 0.0403 moles NaOH we'll have 0.0403 moles NaCl

Step 7: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.0403 moles * 58.44 g/mol

Mass NaCl = 2.35 grams

We can produce 2.35 grams sodium chloride

8 0

4 years ago

Sodium hydroxide reacts with aluminum and water to produce hydrogen gas:2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2

Kay [80]

Answer: 0.147 grams

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al=\frac{1.33g}{27g/mol}=0.049moles$

$\text{Moles of} NaOH=\frac{4.25g}{40g/mol}=0.106moles$

$2Al(s)+2NaOH(aq)+6H_2O(l)\rightarrow Na(Al(OH)_4(aq)+3H_2(g)$

According to stoichiometry :

2 moles of $Al$ require = 2 moles of $NaOH/tex]Thus 0.049 moles of [tex]Al$ will require= $\frac{2}{2}\times 0.049=0.049moles$ of $NaOH$

Thus $Al$ is the limiting reagent as it limits the formation of product and $NaOH$ is the excess reagent.

As 2 moles of $Al$ give = 3 moles of $H_2$

Thus 0.049 moles of $Al$ give = $\frac{3}{2}\times 0.049=0.0735moles$ of $H_2$

Mass of $H_2=moles\times {\text {Molar mass}}=0.0735moles\times 2g/mol=0.147g$

Thus 0.147 g of $H_2$ will be produced from the given masses of both reactants.

6 0

3 years ago

After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?

Bond [772]

Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value. The equation to describe the decay is
Nt=N0(1/2) $^{t/t(1/2)}$ where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time. So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days

5 0

3 years ago

Microwave warming Popcorn is a example of

Viefleur [7K]

Answer:

Explanation:

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4 0

3 years ago

What reaction type is the followong reaction ​

What reaction type is the followong reaction