Let's write some equations.
Mingwei's distance from Town A after

hours from 8:00 is

.
Ali's distance from Town B after

hours is

, since he doesn't start walking for 40 minutes.
When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).
So, this gives

, so

, so

, so the time is 10:40.
After

hours, Mingwei has traveled

kilometers while Ali has traveled sixty, so the distance between the towns is

kilometers.
I'll give a practice problem to help explain it a bit better.
Here, let's try to solve 45% of of 60.
First, we convert the percentage into a decimal. To turn any percentage into a decimal you move the point two spaces to the left.
That means 45% as a decimal is .45.
Next, we multiply our number, 60, by the decimal .45.
60×.45=27.
That means 45% of 60 is 27.
To sum it all up, you have to get the percentage, move the decimal point two spaces to the left, and multiply it by the number you were trying to find the percentage of.
Have a wonderful day! :)
If 1 in.= 2.54 cm, Then !9in. multiplied by 2.54 cm would be b. 48.26 cm
2x^2+3
x=3
2(3)^2+3
2(9)+3
18+3
21 is the answer.
Answer:

Step-by-step explanation:
We want to find the Riemann sum for
with n = 6, using left endpoints.
The Left Riemann Sum uses the left endpoints of a sub-interval:

where
.
Step 1: Find 
We have that 
Therefore, 
Step 2: Divide the interval
into n = 6 sub-intervals of length 
![a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b](https://tex.z-dn.net/?f=a%3D%5Cleft%5B0%2C%20%5Cfrac%7B%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B4%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B4%7D%5Cright%5D%3Db)
Step 3: Evaluate the function at the left endpoints






Step 4: Apply the Left Riemann Sum formula

