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BartSMP [9]
3 years ago
7

Arif ordered a more expensive meals and Keisha. After the tax and tip were figured, he decided he should pay three dollars more

than Keisha. How much should they each pay?
Mathematics
1 answer:
iren [92.7K]3 years ago
8 0
Should pay the amount of $6.86
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Find the value of x if b=8 and a=6
PSYCHO15rus [73]

Answer:

x = 10

Step-by-step explanation:

Using the Pythagorean theorem:

8² + 6² = x²

64 + 36 = x²

x² = 100

x = 10

6 0
2 years ago
Please help! Correct answer only, please! I need to finish this assgnment this week! Matrix P has a dimensions of 3 X 4 and Matr
Temka [501]

Answer: C

Step-by-step explanation:

Your answer is correct! When you multiply 2 matrices, the inner dimensions have to be equal. If they are equal, the resulting dimensions would be the outer dimentions.

(<u>3</u>×4)(4×<u>5</u>)

Since the inner (bolded) dimensions are the same, in this case 4×4, we know these matrices can be multiplied.

Since these matrices can be multiplied, the product will be 3×5, the underlined outer dimensions.

4 0
3 years ago
(1/27)^x-6=27<br><br>Could I please have a step by step as well? Much appreciated! ​
Andrei [34K]

Answer:

x = 7

Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

\frac{1}{ {27}^{x - 8} }  = 27

2) Multiply both sides by 27^x - 8.

1 =  {27} \times 27^{1 + x  - 8}

3) Use the product rule: x^a x^b = x^a+b.

1 =  {27}^{1 + x - 8}

4) Simplify 1 + x - 8 to x - 7.

1  =  {27}^{x - 7}

5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.

log_{27}1 = x - 7

6) Use Change of Base Rule.

\frac{ log_1  }{  log{27} }  = x - 7

7) Use rule of 1: log 1 = 0.

\frac{0}{ log_{27}}  = x - 7

8) Simplify 0/log_27 to 0.

0 = x - 7

9) Add 7 to both sides.

7 = x

10) Switch sides.

x = 7

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>.</u>

5 0
2 years ago
Solve the following system of equations for all three variables.
nignag [31]
  5x - 2y + 1z = 8 ⇒   5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9x -  2y -  5z = 4             -4x + 3z = 13

 5x -  2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9z -  2y -  5z = 4 ⇒ -9x -  2y -  5z = 4
                                        -18x - 3z = 9

     -4x + 3z = 13
    -18x - 3z =   9
           -22x = 22
            -22    -22
                x = -1
    -18x - 3z = 9
-18(-1) - 3z = 9
       18 - 3z = 9
     - 18       - 18
             -3z = -9
              -3     -3
                z = 3

    5x - 2y + z = 8
5(-1) - 2y + 3 = 8
     -5 - 2y + 3 = 8
     -2y - 5 + 3 = 8
           -2y - 2 = 8
                + 2 + 2
                -2y = 10
                 -2     -2
                   y = -5
          (x, y, z) = (-1, -5, 3)
6 0
3 years ago
Someone please help me!!
eduard
On what do you need help
4 0
3 years ago
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