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Zina [86]
3 years ago
9

In lightning , light is seen first and sound is heard later it is due to

Physics
2 answers:
Maksim231197 [3]3 years ago
8 0

Answer:

option 4

Explanation:

Light's velocity in air ( 3 × 10^8 m/s ) is much greater than sound's velocity in air ( 343 m/s )

Hence due to difference in velocities , during lightning light is seen first & sound is heard later

Dvinal [7]3 years ago
6 0
#4 is the correct answer !! :)))
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A new company is making security cameras. These security cameras will be different than other security cameras because instead o
babunello [35]

Answer:

b

Explanation:

4 0
2 years ago
The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s
notka56 [123]

Answer:

     P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

           I = P / A

Since sound is distributed in all directions spherical shape, the area of ​​a sphere is

           A = 4π r²

let's clear the power and replace

         P = I A

         P = I (4π r²)

let's calculate

         P = 5.00 (4π 2²)

         P = 251, 3 W

6 0
4 years ago
Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
bekas [8.4K]

The correct answer is the following.

The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.

As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.

5 0
3 years ago
A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:
34kurt

Answer:

a) v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

b) v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

c) v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

d) v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

Explanation:

For this case we know that the velocity is v = 200 cm/s = 2m/s

v_f represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

v = \sqrt{\frac{T}{\rho}}

And the linear density is defined as:

\rho = \frac{m}{L}

And if we replace this we got:

v = \sqrt{\frac{TL}{m}}

If the tension mass is doubled we have this:

v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

Part b

If we mass is quadrupled we have this:

v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

7 0
3 years ago
A light-emitting diode (LED) connected to a 3.0 V power supply emits 440 nm blue light. The current in the LED is 11 mA , and th
zimovet [89]

Answer:

3.73 * 10^16   photons/sec

Explanation:

power supply = 3.0 V

Emits 440 nm blue light

current in LED = 11 mA

efficiency of LED = 51%

<u>Calculate the number of photons per second the LED will emit </u>

first step : calculate the energy of the Photon

E = hc / λ

   =(  6.62 * 10^-34 * 3 * 10^8 )  / 440 * 10^-9

   = 0.0451 * 10^-17  J

Next :

Number of Photon =( power supply * efficiency * current ) / energy of photon

= ( 3 * 0.51 * 11 * 10^-3 ) / 0.0451 * 10^-17

= 3.73 * 10^16 photons/sec

3 0
3 years ago
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