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3 years ago

In lightning , light is seen first and sound is heard later it is due to

Physics

2 answers:

Maksim231197 [3]3 years ago

8 0

Answer:

option 4

Explanation:

Light's velocity in air ( 3 × 10^8 m/s ) is much greater than sound's velocity in air ( 343 m/s )

Hence due to difference in velocities , during lightning light is seen first & sound is heard later

Dvinal [7]3 years ago

6 0

#4 is the correct answer !! :)))

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Maksim231197 [3]

Answer:

all of the above????

Explanation:

my teacher told me.

8 0

3 years ago

Which statement correctly describes the gravitational potential energy of the pendulum based on this diagram?

MrRa [10]

I think it's 'C' but I won't know for sure until you let me see the diagram.

8 0

3 years ago

PLEASE HELP I need the answer to this question ASAP

cestrela7 [59]

Answer:

answer is A

Explanation:

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7 0

2 years ago

Read 2 more answers

A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?

vovikov84 [41]

Answer:

30N in the direction the 45N acts.

Explanation:

Fnet = F1 + F2 (the vector sum of the forces)

Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:

Fnet = 45 - 15

Fnet = 30N

Since the answer is positive, it is in the direction the 45N force acts.

7 0

3 years ago

A lumberjack (mass = 110 kg) is standing at rest on one end of a floating log (mass = 206 kg) that is also at rest. The lumberja

Lemur [1.5K]

Answer:

a). The velocity of the first log is -1.65 m/s.

(b). The velocity of the second log is 1.07 m/s.

Explanation:

Given that,

Mass of lumberjack M= 110 kg

Mass of log m= 206 kg

Final velocity = 3.09 m/s

(a). We need to calculate the velocity of the first log just before the lumberjack jumps off

Using conservation of momentum

$Mu_{1}+mu_{2}=Mv_{1}+mv$

Put the value into the formula

$0=110\times3.09+206v$

$v=-\dfrac{110\times3.09}{206}$

$v=-1.65\ m/s$

The velocity of the first log is -1.65 m/s.

(b). If the lumberjack comes to rest relative to the second log

We need to calculate the velocity of the second log

$(M+m)v=Mv_{1}$

$v=\dfrac{Mv_{1}}{M+m}$

Put the value into the formula

$v=\dfrac{110\times3.09}{110+206}$

$v=1.07\ m/s$

The velocity of the second log is 1.07 m/s.

Hence, (a). The velocity of the first log is -1.65 m/s.

(b). The velocity of the second log is 1.07 m/s.

4 0

3 years ago