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Zina [86]
3 years ago
9

In lightning , light is seen first and sound is heard later it is due to

Physics
2 answers:
Maksim231197 [3]3 years ago
8 0

Answer:

option 4

Explanation:

Light's velocity in air ( 3 × 10^8 m/s ) is much greater than sound's velocity in air ( 343 m/s )

Hence due to difference in velocities , during lightning light is seen first & sound is heard later

Dvinal [7]3 years ago
6 0
#4 is the correct answer !! :)))
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A 50.0 g toy car is released from rest on a frictionless track with a vertical loop of radius R (loop-the-loop). The initial hei
Mariana [72]

Answer:

the speed of the car at the top of the vertical loop  v_{top} = 2.0 \sqrt{gR \ \ }

the magnitude of the normal force acting on the car at the top of the vertical loop   F_{N} = 1.47 \ \ N

Explanation:

Using the law of conservation of energy ;

mgh = mg (2R) + \frac{1}{2}mv^2_{top}\\\\mg ( 4.00 \ R) = mg (2R) + \frac{1}{2}mv^2_{top}\\\\g(4.00 \ R) = g (2R) + \frac{1}{2}v^2 _{top}\\\\v_{top} = \sqrt{2g(4.00R - 2R)}\\\\v_{top} = \sqrt{2g(4.00-2)R

v_{top} = 2.0 \sqrt{gR \ \ }

The  magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:

F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\

F_{N} = 1.47 \ \ N

4 0
3 years ago
A cat is sleeping on the dashboard of a moving car. Imagine that the cat does not wake up and is not touched by anything. Use Ne
Minchanka [31]
What do we call an object displaced by an unbalanced Force,
Accelerated object,


And we also know that,
Due to acceleration, An object displaces.

But I'll use Newton's 1st law to prove it,
Which is, An object will remain in rest or in uniform motion until it is compelled by an external Force.

As per the his law,
The cat will remain on the dashboard of that moving car until it is compelled by Air Force (external Force).

!! Hope It Helps !!
7 0
3 years ago
What gravitational force does the moon produce
saul85 [17]

Answer:

1.94\cdot 10^{20} N

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

m_1 = 5.98\cdot 10^{24}kg is the mass of the Earth

m_2 = 7.34\cdot 10^{22} kg is the mass of the Moon

r=3.88\cdot 10^8 m is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(5.98\cdot 10^{24})(7.34\cdot 10^{22})}{(3.88\cdot 10^8)^2}=1.94\cdot 10^{20} N

6 0
3 years ago
Calculate the velocity of the object in the graph during the following time interval 0-6 seconds. Also, during which time interv
cestrela7 [59]
Its accelarating from 1-10 i know that because the line is going up. i hope i helped
3 0
2 years ago
Help:choose the correct statement plz​
alexira [117]

Answer:

Second one

Explanation:

Lying on the floor is something you can do with the least amount of energy

7 0
2 years ago
Read 2 more answers
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