Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
1 answer:
Answer:
Answer:
1.1 x 10^9 ohm metre
Explanation:
diameter = 1.5 mm
length, l = 5 cm
Potential difference, V = 9 V
current, i = 230 micro Ampere = 230 x 10^-6 A
radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m
Let the resistivity is ρ.
Area of crossection
A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2
Use Ohm's law to find the value of resistance
V = i x R
9 = 230 x 10^-6 x R
R = 39130.4 ohm
Use the formula for the resistance
ρ = 1.1 x 10^9 ohm metre
Explanation:
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The displacement is 2 m south
Explanation:
Distance and displacement are two different quantities:
- Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
- Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points
For the car in this problem, the motion is:
10 m south
8 m north
Taking north as positive direction, we can describe the two parts of the motion as
m
Therefore, the final position of the car with respect to the original position is
which means 2 m south: so, the displacement of the car is 2 m south.
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Explanation:
Let us assume that moment about the pin and then setting it equal to zero as the rod is in equilibrium is as follows.
Moment = Force × Leverage
= 0
Therefore, we can conclude that the force () in the cable by assuming that the origin of our coordinate system is at the rod’s center of mass is 935.11 N.