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3 years ago

Newton's Third Law predicts that during a collision between two carts, when the sum of the forces acting on the system are zero:

Physics

1 answer:

Naily [24]3 years ago

6 0

Answer:

The two carts will experience an impulse of the same magnitude, but of opposite directions.

Explanation:

Newton's third law proves that though action and reaction are the same, but they are opposite to each other.

i.e $F_{1}$ = - $F_{2}$

where: $F_{1}$ and $F_{2}$ have equal value.

Impulse = F x t

where F is the force on the object and t is the time of impact.

In the given question, since the collision takes place in a given time.

Then;

$F_{1}$ x $t_{1}$ = - $F_{2}$ x $t_{2}$

⇒ $F_{1}$ $t_{1}$ = - $F_{2}$ $t_{2}$

Thus, since the sum of the forces acting on the system are zero, then the two carts experience an impulse of the same magnitude but opposite in directions.

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Find the moments of inertia Ix, Iy, I0 for a lamina that occupies the part of the disk x2 y2 ≤ 36 in the first quadrant if the d

Tasya [4]

Answer:

I(x) = 1444×k × ${\pi}$

I(y) = 1444×k × ${\pi}$

I(o) = 3888×k × ${\pi}$

Explanation:

Given data

function = x^2 + y^2 ≤ 36

function = x^2 + y^2 ≤ 6^2

to find out

the moments of inertia Ix, Iy, Io

solution

first we consider the polar coordinate (a,θ)

and polar is directly proportional to a²

so p = k × a²

so that

x = a cosθ

y = a sinθ

dA = adθda

I(x) = ∫y²pdA

take limit 0 to 6 for a and o to $\pi /2$ for θ

I(x) = $\int_{0}^{6}\int_{0}^{\pi/2}$ y²p dA

I(x) = $\int_{0}^{6}\int_{0}^{\pi/2}$ (a sinθ)²(k × a²) adθda

I(x) = k $\int_{0}^{6}a^(5)$ da × $\int_{0}^{\pi/2}$ (sin²θ)dθ

I(x) = k $\int_{0}^{6}a^(5)$ da × $\int_{0}^{\pi/2}$ (1-cos2θ)/2 dθ

I(x) = k $({r}^{6}/6)^(5)_0$ × ${θ/2 - sin2θ/4}^{\pi /2}_0$

I(x) = k × $({6}^{6}/6)$ × ( ${\pi /4} - sin\pi /4)$

I(x) = k × $({6}^{5})$ × ${\pi /4}$

I(x) = 1444×k × ${\pi}$ .....................1

and we can say I(x) = I(y) by the symmetry rule

and here I(o) will be I(x) + I(y) i.e

I(o) = 2 × 1444×k × ${\pi}$

I(o) = 3888×k × ${\pi}$ ......................2

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3 years ago

When electric current is flowing in a metal, the electrons are movinga. at nearly the speed of light.b. at the speed of sound in

yaroslaw [1]

Answer:

Option (d)

Explanation:

The electrons in a conductor moves with the drift velocity when the electric current is flowing through the conductor.

The drift velocity is due to the applied electric field across the conductor.

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3 years ago

A compass in a magnetic field will line up __________.

Anastaziya [24]

Line up in a direction parallel to the magnetic field lines<span />

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4 years ago

What is net netforce?

melisa1 [442]

In mechanics, the net force is the vector sum of forces acting on a particular or object

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3 years ago

Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t

marshall27 [118]

Answer:

x = 240 m

Explanation:

This is a kinematics exercise

Let's fix our frame of reference on car A

x = x₀ₐ+ v₀ₐ t + ½ aₐ t²

the initial position of car a is zero

x = 0 + v₀ₐ t + ½ 0.8 t²

for car B

x = x_{ob} + v_{ob} t - ½ a_b t²

car B's starting position is 30 m

x = 30 + v_{ob} t - ½ 0.4 t²

at the point where they meet, the position of the two vehicles is the same

0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²

let's reduce the speeds to the SI system

v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s

v_{ob} = 23.4 km / h = 6.5 m / s

4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²

0.2 t² - 2.5 t - 30 = 0

t² - 12.5 t - 150 = 0

we solve the quadratic equation

t = $\frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150} }{2}$

t = $\frac{12.5 \ \pm 27.5}{2}$

t₁ = 20 s

t₂ = -7.5 s

time must be a positive quantity so the correct result is t = 20 s

let's look for the distance

x = 4 t + ½ 0.8 t²

x = 4 20 + ½ 0.8 20²

x = 240 m

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3 years ago