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4 years ago

13. Sound waves can't travel through

Physics

2 answers:

xz_007 [3.2K]4 years ago

7 0

They cannot travel through D a vacuum. They need a solid, liquid or gas to travel

faust18 [17]4 years ago

7 0

D. a vacuum is the correct answer.

Because there are no particles in vacuum to transfer sound waves.

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If the moon moved closer to the earth, how would the gravitational force between them change?.

hichkok12 [17]

If the moon moved closer to the earth, The gravitational force between them will increase.

This can be understood by Newton's law of universal gravitation. This is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

$F_{gravitation}$ = G $\frac{M_{1} M_{2}}{r^{2} }$

If the moon moved closer to earth, the distance between them will be reduced, and as the force of gravitation is inversely proportional to the distance between the masses, the gravitation force increases.

Learn more about gravitation force here

brainly.com/question/12528243

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2 years ago

A 900 kg car runs into a 70 kg deer at 28 m/s. If the car transfers all of its momentum to the deer, how fast does the deer go f

Alex

Answer:

Mc = 900 Kg

Uc = 28 ms^-1

Md = 70 Kg

Ud = 0

We want Vd

Vc = Vd

This situation is elastic momentum

$m _{c}u _{c}+ m _{d}u _{d} = m _{c}v _{c} + m _ dv _{d} \\ (900 \times 28) + (70 \times 0) = (900 \times v _{d} ) + (70 \times v _{d}) \\ 25200 = (900 + 70)v _{d} \\ 25200 = 970v _{d} \\ v _{d} = \frac{25200}{970} \\ v _{d} = 26 \: m {s}^{ - 1}$

4 0

3 years ago

Convert 60 km/ hr into m/s

elixir [45]

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second

4 0

3 years ago

Difference between effort and load

scoray [572]

Answer:

Effort is the unaltered force. Load is the altered force.

4 0

3 years ago

A student launches a small 0.5 kg rocket with an initial speed of 30 m/s at an angle of 60°. Approximately how much time will th

Elena L [17]

Answer:

$t=5.30s$

Explanation:

The high reached by a proyectile in an uniformly accelerated motion is given by:

$y=v_{0y}t-\frac{gt^2}{2}$

The time that the rocket spends in the air is obtained for y = 0, since this is the time that the rocket travels before touching the ground. Recall that $v_{0y}=v_0sin\theta$ . Solving for t:

$0=(v_0sin\theta) t-\frac{gt^2}{2}\\\frac{gt}{2}=v_0sin\theta\\t=\frac{2v_0sin\theta}{g}\\t=\frac{2(30\frac{m}{s})sin(60^\circ)}{9.8\frac{m}{s^2}}\\t=5.30s$

5 0

4 years ago