All categories

2 years ago

Which rule(s) is used for combining velocities?

Physics

1 answer:

DIA [1.3K]2 years ago

4 0

Answer: B. Vector rules

Explanation:

You might be interested in

Which of the following types of energy is not associated with a car engine?

soldi70 [24.7K]

Answer:

Explanation:

Does not assosicate with Light

4 0

2 years ago

A jetliner has a velocity of 95 m/s. What is the displacement of the jetliner at t=3.0 seconds?

charle [14.2K]

Distance = speed / time

speed = 95 m/s
time = 3 s

distance = 95 / 3 m

displacement = 95/3 m or 32 m (2 s.f.)

5 0

2 years ago

What in earth's atmosphere helps most to absorb uvb ultraviolet light from the sun?

Whitepunk [10]

The Ozone layer in the atmosphere absorbs the UV rays

Hope it helps!

4 0

2 years ago

A 23.9 g sample of iridium is heated to 89.7 oC, and then dropped into 20.0 g of water in a coffee-cup calorimeter. The temperat

Nikolay [14]

Answer:

The specific heat capacity of iridium = 0.130 J/g°C

Explanation:

Assuming no heat losses to the environment and to the calorimeter,

Heat lost by the iridium sample = Heat gained by water

Heat lost by the iridium sample = mC ΔT

m = mass of iridium = 23.9 g

C = specific heat capacity of the iridium = ?

ΔT = change in temperature of the iridium = 89.7 - 22.6 = 67.1°C

Heat lost by the iridium sample = (23.9)(C)(67.1) = (1603.69 C) J

Heat gained by water = mC ΔT

m = mass of water = 20.0 g

C = 4.18 J/g°C

ΔT = 22.6 - 20.1 = 2.5°C

Heat gained by water = 20 × 4.18 × 2.5 = 209 J

Heat lost by the iridium sample = Heat gained by water

1603.69C = 209

C = (209/1603.69) = 0.130 J/g°C

7 0

2 years ago

Read 2 more answers

A spherical hot air balloon of diameter 30.0 meters just floats (hovers) when the hot air inside has been heated to a density of

Rom4ik [11]

Answer:

W = 166422.729 N

Explanation:

given,

diameter of the balloon = 30 m

density of the air = 1.10 Kg/m³

weight of the balloon and cargo = ?

density of the surrounding air = 1.20 kg/m³

we know,

Density = mass/volume

m = density x volume

$m = \rho\times \dfrac{4}{3}\pi r^3$

$m =1.20 \times \dfrac{4}{3}\pi\times 15^3$

m = 16964.6 Kg

Weight of the balloon

W = m g

W = 16964.6 x 9.81

W = 166422.729 N

Weight of the balloon and the cargo is equal to W = 166422.729 N

5 0

2 years ago