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joja [24]
3 years ago
7

Which rule(s) is used for combining velocities?

Physics
1 answer:
DIA [1.3K]3 years ago
4 0

Answer: B. Vector rules

Explanation:

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What are the differences between concave lens and concave mirrors?
Pavel [41]

Explanation:

A concave mirror can form real, inverted images of various sizes and virtual, erect and enlarged images whereas a concave lens forms only virtual, errect and diminished images.

8 0
3 years ago
A 1.5V battery is connected to a small light bulb with a resistance of 3.5 what is the current in the bulb?
notka56 [123]

Technically, we don't have the information needed to calculate the current,
because you haven't mentioned the units of the 3.5 .

Since the 3.5 is a resistance, we strongly suspect ... and we'll therefore
assume ... that the  3.5  has the units of ohms.    Then . . .

  Current = (voltage) / (resistance)  =  (1.5/3.5) = <em>3/7 of an Ampere</em>.

                                                                   (429 mA, rounded)


5 0
3 years ago
What is the average speed of an object travels 60 meters in 3 seconds?
Solnce55 [7]

Answer:

20 metres per second

Explanation:

60/3

7 0
3 years ago
34)You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then
velikii [3]

Answer:

F_H_n=230.04 N

The Required  horizontal force is 230.04N

Explanation:

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F_H_n=F_f\\F_h=mg*u

where:

F_{Hn} is the required Force

u is the friction coefficient

m is the mass

g is gravitational acceleration=9.8m/s^2

200=mg*u                         Eq (1)

Now, weight increases by 42% and friction coefficient decreases by 19%

New weight=(1.42*m*g) and new friction coefficient=0.81u

F_H=(1.42m*g*.81u)          Eq (2)

Divide Eq(2) and Eq (1)

\frac{F_H_n}{200}=\frac{1.42m*g*0.81u}{m*g*u}\\F_H_n=1.42*0.81*200\\F_H_n=230.04 N

The Required  horizontal force is 230.04N

4 0
3 years ago
The heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?
nataly862011 [7]

Answer:

hey!

Your answer will be EXACTLY 113.97899 Pounds

Explanation:

BUT IF YOU ROUND THIS UP TO THE WHOLE NUMBER etc IT WILL BECOME 114 POUNDS!

Hope This Helped!

itsMATT04

3 0
3 years ago
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