Question

What volume in liters will be occupied by 1.20 moles of helium gas at a pressure of 3.675 atm and 100*C?

Answer 1

Answer:

V = 121.82 L

Explanation:

Given data:

Number of moles of gas = 1.20 mol

Pressure of gas = 3.675 atm

Temperature = 100°C

Volume occupied = ?

Solution:

Formula:

General gas equation:

PV = nRT

R = general gas constant.

Now we will convert the temperature into kelvin.

100+273 = 373 K

V = nRT/P

V = 1.2 mol × 0.0821 atm.L/mol.K × 373 K / 3.675 atm

V = 447.68 / 3.675 atm

V = 121.82 L