Answer:
See the answer below
Explanation:
The cross that would produce the maximum number of offspring with green sea pods would be:
1. GG x GG, or
2. GG x gg
The first one would produce all green offspring with homzygous genotypes as follows:
GG x GG
GG GG GG GG
The second cross would produce all green offspring with heterozygous genotypes as follows:
GG x gg
Gg Gg Gg Gg
Calcium Phospate formula: Ca3(PO4)2
Atomic weight:
Ca = 40 ; P = 31 ; O = 16
Ca3 = 40 * 3 = 120
P = 31
O4 = 16 * 4 = 64
(PO4)2 = (31 + 64) * 2 = 95 * 2 = 190
Ca3(PO4)2 = 120 + 190 = 310 g/mol
31/310 = 10% P in the calcium phospate
1.00kg * 1000 g/kg = 1000 g of phosphorus.
1000 g / 10% = 10,000 g of calcium phosphate
10,000 g / 58.5% = 17,094 grams of ore.
The minimum mass of the ore should be 17,094 grams or 17.094 kg.
A. Mass of the unknown gas.
The mass of the unknown gas is calculated by subtracting the weight of the empty flask from the mass when there was air in it.
m = 126.593 g - 125.623 g
Simplifying,
m = 0.97 grams
b. Molar mass of the gas
The molar mass of the gas is calculated by the ideal gas law.
PV = (m/M)RT
where P is pressure,V is volume, m is the mass, M is the molar mass, R is the universal gas constant, and T is temperature. Substituting the known values to the equation,
(733 mmHg/760 mmHg/atm)(0.20 L) = (0.97 g/M)(0.0821 L.atm/molK)(99 + 273.15 K)
The value of M in the equation is 153.64 g/mol.
<em>Answer: 153.64 g/mol</em>