Answer:
79.0 g
Explanation:
1. Gather the information in one place.
MM: 148.89 253.81
2NaI + Cl2 → I2 + 2NaCl
m/g: 67.3
2. Moles of I2
n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2
2. Moles of NaI needed
From the balanced equation, the molar ratio is 2 mol NaI: 1 mol I2
n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI
3. Mass of NaI
m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI
It takes 79.0 g of NaI to produce 67.3 g of I2.
Helium,neon,argon,krypton, and xenon
So,
These species react stoichiometrically. Thus, we can say, for example, that 1 mol A is stoichiometrically equivalent to 1 mol B in this reaction. I will say A = B.
A = B
A = C
A = D
B = C
B = D
C = D
As you can see, there are more than 4 distinct mole ratios for this reaction. Thus, the statement is false.
