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3 years ago

What is the [OH-] concentration of a solution with a pH of 5.5?

Chemistry

2 answers:

aleksley [76]3 years ago

5 0

Answer:

Explanation:

grandymaker [24]3 years ago

5 0

Answer:
C
Explanation:

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3 years ago

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2 years ago

26 Milkweed contains a poison known as cardenolides. Monarch butterflies eat the milkweed plant and hold on to this toxic compou

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Cardenolides, with the chemical formula CH₁₈C₂₀H₁₅CHCO₂ have (D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms.

Milkweed contains a poison known as cardenolides. The chemical formula for cardenolides CH₁₈C₂₀H₁₅CHCO₂.

The subscripts in the formula represent the atomicities, that is the number of atoms of each element in each part of the formula.

We can calculate the total number of atoms of each element by adding its atomicities.

<h3>Carbon atoms</h3>

$C = 1 + 20 + 1 + 1 = 23$

<h3>Hydrogen atoms</h3>

$H = 18 + 15 + 1 = 34$

<h3>Oxygen atoms</h3>

$O = 2$

Cardenolides, with the chemical formula CH₁₈C₂₀H₁₅CHCO₂ have (D) 23 carbon atoms, 34 hydrogen atoms, and 2 oxygen atoms

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3 years ago

Ethanol can react with hydrochloric acid to form chloroethane and water. When sulfuric acid is added, the

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Answer: 1.Sulfuric acid is a catalyst

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3 years ago

25.0 mL of a hydrofluoric acid solution of unknown concentration is titrated with 0.200 M NaOH. After 20.0 mL of the base soluti

lesantik [10]

Answer:

[HF]₀ = 0.125M

Explanation:

NaOH + HF => NaF + H₂O

Adding 20ml of 0.200M NaOH into 25ml of HF solution neutralizes 0.004 mole of HF leaving 0.004 mole NaF in 0.045L with 0.001M H⁺ at pH = 3. This is 0.089M NaF and 0.001M HF remaining.

=> 45ml of solution with pH = 3 and contains 0.089M NaF from titration becomes a common ion problem.

HF ⇄ H⁺ + F⁻

C(eq) [HF] 10⁻³M 0.089M (<= soln after adding 20ml 0.200M NaOH)

Ka = [H⁺][F⁻]/[HF]₀ => [HF]₀ = [H⁺][F⁻]/Ka

[HF]₀ = (0.001)(0.089)/(7.1 x 10⁻⁴) M = 0.125M

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3 years ago