Answering pretty sure yes
Step-by-step explanation:
Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
The square root of 98 is 9.899<span> so I think if it was rounded to the nearest tenth it would be 9.9</span>
The slope intercept form is y = mx + b
you need to find the equation that has a slope of 3/4 and passes through (4,1/3)
Plug in the given into the equation
y = 3/4x + b
to solve for the y-intercept, plug in the given coordinate that the line passes through
1/3 = 3/4(4) + b
1/3 = 3 + b
subtract 3 from both sides
-8/3 = b
now back to the slope intercept equation
y = mx + b
plug in the slope and y-intercept
y = 3/4x - 2 2/3
or
y = 3/4x - 8/3
Hope this helps :)
