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butalik [34]
3 years ago
11

2cos2ysin2ysimplify​

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Reorder 2 cos (2y) and sin (2y)

= sin (2y)(2 cos(2y))

Remove parenthesis

= sin (2y) * 2 cos (2y)

Reorder sin (2y) and 2

= 2 * sin (2y) cos (2y)

Apply the sine double-angle identity

= sin (2(2y))

Now multiply 2 by 2

<u>= sin (4y) </u>

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Choose the correct simplification of the expression a^7b^8/a^4b^4
Alex787 [66]
The answer is B: a^3b^4<span>

Proof:
Simplify the following:
(a^7 b^8)/(a^4 b^4)

Combine powers. (a^7 b^8)/(a^4 b^4) = a^(7 - 4) b^(8 - 4):
a^(7 - 4) b^(8 - 4)

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PS: I just wish that you put the equation down as it's intended i.e.
a^7b^8/a^4b^4 is not the same as (<span>a^7b^8)/(a^4b^4)</span>
</span>
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