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JulsSmile [24]
3 years ago
6

A solution has a22.0*10^-6 H30^+ Calculate the OH^- and pH of this solution, be sure to show work.

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
6 0

Answer:

pH= 4.66

OH^- = 4.55*10^-10

Explanation:

So H3O^+ means the same thing as [H^+].

so pH= -log(22.0*10^-6)

pH= 4.66

To find [OH^-]

[H^+] [OH^-] = 1*10^-14

1*10^-14 / 22.0*10^-6 = 4.55*10^-10= OH^-

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Viscous Drag.

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Explanation:

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8 0
3 years ago
How many protons, neutrons, and electrons make up an ion of
yKpoI14uk [10]

Answer:

protons=15

electron=15

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6 0
3 years ago
Consider the letters in the word Chemistry. Use them to make as many word compounds as is possible with 9 elements. How is an el
dimaraw [331]
<span>The difference between an element and a compound is that an element is a substance made of same type of atoms, whereas a compound is made of different elements in definite proportions. Examples of elements include iron, copper, hydrogen and oxygen. Examples of compounds include water (H2O) and salt (Sodium Chloride - NaCl) </span>
6 0
3 years ago
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce
Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{3.49}{3.50}=0.997g

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{9.00}{6.00}=1.5g

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0
3 years ago
What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?
galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

Cu^{2+}(aq) + 2e^-\rightarrow      Cu(s)

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = \frac{63.55 \times208800}{2\times96487}

                                                         = 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

brainly.com/question/22104403

#SPJ4

4 0
1 year ago
Read 2 more answers
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