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Harrizon [31]
3 years ago
6

How does the law conservation of matter apply to machines

Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0
The Law of Conservation of Matter says that the amount of matter stays the same, even when matter changes form. ... Another way to explain the law of conservation of matter is to say that things cannot be magically created or destroyed. Please mark brainliest?
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QUESTION 5
mrs_skeptik [129]
Answer is b. Hope it help
7 0
3 years ago
The discovery of protons and electrons most directly refuted or replace the idea that
Effectus [21]

Answer:

The atom resembles plum pudding

Explanation:

The discovery of the electron in 1897 by J. J Thomson and the proton in 1917 by Rutherford most directly refuted or replace the idea that the atom resembles plum pudding.

8 0
3 years ago
What is the oxidation half-reaction for this unbalanced redox equation? cr2o72– + fe2+ → cr3+ + fe3+ cr3+ → cr2o72– cr2o72– → cr
KatRina [158]

Answer:

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

Explanation:

The balanced oxidation half equation is;

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.

The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;

Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)

It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.

4 0
3 years ago
How many joules of energy do you have if you have 0.45 L of water in a can and you heat the 23C water to 55C site:socratic.org
Bess [88]

Answer:

Q = 60192 j

Explanation:

Given data:

Volume of water = 0.45 L

Initial temperature = 23°C

Final temperature = 55°C

Amount of heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  55°C - 23°C

ΔT = 32°C

one L = 1000 g

0.45 × 1000 = 450 g

Specific heat capacity of water is 4.18 j/g°C

Q = m.c. ΔT

Q = 450 g.  4.18 j/g°C.  32°C

Q = 60192 j

4 0
3 years ago
Is oil and water a solution, colloid, or suspension?
Ulleksa [173]
Emulsions are an example of colloids<span> composed of tiny particles </span>suspended<span> in another immiscible (unmixable) material. An emulsion is a </span>suspension<span> of two liquids that usually do not mix together. These liquids that do not mix are said to be immiscible. An example would be </span>oil and water<span>.
INFORMATION HOPE THIS HELPED! PLEASE MARK ME AS BRAINLIEST THANK YOU.

</span>
7 0
3 years ago
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