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3 years ago

How does the law conservation of matter apply to machines

1 answer:

5 0

The Law of Conservation of Matter says that the amount of matter stays the same, even when matter changes form. ... Another way to explain the law of conservation of matter is to say that things cannot be magically created or destroyed. Please mark brainliest?

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All atoms of the same element have the same what?

Paraphin [41]

Answer:

must have the same number of protons

8 0

2 years ago

4 Al + 3 O2 --> 2 Al2O3

SIZIF [17.4K]

Answer:

The answer to your question is 7.4 moles of Aluminum

Explanation:

Data

moles of Al = ?

moles of Al₂O₃ = 3.7

Balanced chemical reaction

4 Al + 3 O₂ ⇒ 2 Al₂O₃

To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical equation.

4 moles of Aluminum ----------------- 2 moles of Al₂O₃

x ----------------- 3.7 moles of Al₂O₃

x = (3.7 x 4) / 2

x = 14.8 / 2

x = 7.4 moles of Aluminum

5 0

3 years ago

Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to

zhenek [66]

Answer:

D. It will decrease by a factor of 4

Explanation:

According to the question , the equation follows :

$A+B\rightarrow C+D$

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

$Rate\ \alpha [A]^{a}[B]^{b}$

$r=[A]^{a}[B]^{b}$ .................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

$r'=[A']^{a}[B']^{b}$

Put the value of [A'] , [B'] and r' in the above equation:

$2r=[2A]^{a}[B]^{b}$ ...........(2)

Divide equation (1) by (2) we , get

$\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}$

$2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}$

Here A and A cancel each other

B and B cancel each other

We get,

$2= 2^{a}\times 1^{b}$

1^b = 1 ( power of 1 = 1)

$2= 2^{a}$

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1 = 2

b = 2

Hence the rate law becomes :

$r=[A]^{a}[B]^{b}$

$r=[A]^{1}[B]^{2}$ .............(3)

Look in the question now, it is asked to calculate the concentration of [B],if cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

$r'=[A]^{1}[B']^{2}$

$r'=[A]^{1}(\frac{1}{2}[B])^{2}$

$r'=\frac{1}{4}[A]^{1}[B]^{2}$ ............(a)

But

$r=[A]^{a}[B]^{b}$ ..............(b)

Compare equation (a) and (b) , we get

new rate r' =

r' = 1/4 r

7 0

3 years ago

The movement of molecules across a membrane from an area of high concentration to one of low concentration is best described as:

mestny [16]

Answer:

Difussion

Explanation:

Diffusion is the result of a totally random phenomenon in which the molecules of a fluid come and go between two vessels that can be connected by a pipe. These molecules travel in a single direction, where the solute is more concentrated to where it is more diluted.

This movement of particles will be modified according to the length or area of the pipe and the concentration of solute. The greater the difference in solute concentration along the tube, the greater the diffusion

6 0

3 years ago

If A and B have the SAME mass. A floats and B sinks. B MUST have a

Alexandra [31]

Answer:

volume

Explanation:

6 0

3 years ago

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