Supersaturation is a solution that contains more of the dissolved material than could be dissolved by the solvent under normal circumstances. It can also refer to a vapor of a compound that has a higher (partial) pressure than the vapor pressure of that compound.
Answer:
0.005 M
Explanation:
Given data:
volume of sample solution ( volume of D ) = 5.0 mL
volume of added stock solution ( V1 ) = 5.0 mL
concentration of added stock solution ( N1 ) = 0.02 M
Total volume of concentration ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)
concentration of Total volume of sample ( C2 ) = 0.01
N2 = ( N1V1 ) / V2
= ( 0.02 * 5 ) / 10 = 0.01 m
absorbance of sample solution ( A1 ) = 0.10
absorbance of additional sample solution ( A2 ) = 0.20
attached below is the remaining part of the detailed solution
The answer is silicates!!! Hope this helps!!!
The volume of a box with length 25 cm, height 25 cm and width 1.0 m is 0.0625m³.
Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.
Volume of the box is given by the product of the length of the box, Height of the box and Breadth or width of the box.
Since, the box is a cuboid, hence the formula is given by the products of length, breadth and height.
Given,
length of the box= 25cm = 0.25m
Height of the box =25cm = 0.25m
width of the box= 1m
Volume = length × width × height of box
Volume = 0.25 × 0.25 × 1
Volume = 0.0625m³
The volume of the box is 0.0625m³.
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Answer:
Na = 32.4% , % S = 22.6% and %O = 45.0%
Explanation:
% Na = 3.4/10.5. × 100%
= 32.4%
%S = 2.37/10.5 × 100%
= 22.6%
% O= 4.73/10.5 × 100%
= 45.0%xplanation:
