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iris [78.8K]
3 years ago
8

Fill in the missing spaces in the chart. Will give brainliest.

Chemistry
1 answer:
lana [24]3 years ago
3 0

Explanation:

9/4 Be +2 (the 9 and 4 are stacked next to Be). Atomic #: 4

Mass #: 9, # protons: 4, # neutrons: 5, #electrons: 2.

31/15 P (31 is stacked over 15 next to the P). Atomic #: 15,

Mass #: 31, # protons: 15, # neutrons: 16, # electrons: 15.

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Give the name and formula of the compound formed when a Mn2+ cation combines with a (PO4)3- anion
alex41 [277]
Sodium mn2 and po4  makes sodium
3 0
3 years ago
What type of force holds particles together ?​
Rashid [163]

Answer:

strong nuclear force

Explanation:

4 0
3 years ago
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate th
Andreas93 [3]

Complete question:

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.

Answer:

the heat of combustion of the methanol is 402.31 kJ/mol

Explanation:

Given;

mass of water, m_w = 100 g

initial temperature of water, t₁ = 28 ⁰C

final temperature of water, t₂ = 58 ⁰C

specific heat capacity of water = 4.184 J/g⁰C

reacting mass of the methanol, m = 1.00 g

molecular mass of methanol = 32.04 g/mol

number of moles = 1 / 32.04

                             = 0.0312 mol

Apply the principle of conservation of energy;

n\Delta H_{methanol} = Q_{water}\\\\n\Delta H_{methanol} =  mc\Delta t\\\\n\Delta H_{methanol} =  100 \times 4.184\times (58-28)\\\\n\Delta H_{methanol} =  12,552 \ J\\\\n\Delta H_{methanol} =  12.552 \ kJ\\\\\Delta H_{methanol} = \frac{12.552}{n} \\\\H_{methanol} = \frac{12.552 \ kJ}{0.0312 \ mol} \\\\\Delta H_{methanol} = 402.31 \ kJ/mol

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol

                       

5 0
3 years ago
What is the empirical formula for a substance that contains 3.730% hydrogen, 44.44% carbon, and 51.83% nitrogen by mass?\?
Vlada [557]

Given data:

Hydrogen (H) = 3.730 % by mass

Carbon (C) = 44.44%

Nitrogen (N) = 51.83 %

This means that if  the sample weighs 100 g then:

Mass of H = 3.730 g

Mass of C = 44.44 g

Mass of N = 51.83 g

Now, calculate the # moles of each element:

# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles

# moles of C = 44.44/12 = 3.703 moles

# moles of N = 51.83/14 = 3.702 moles

Divide by the lowest # moles:

H = 3.730/3.702  = 1

C = 3.703/3.702 = 1

N = 3.702/3.702 = 1

Empirical Formula = HCN

3 0
3 years ago
ZINC help asap
bazaltina [42]
Atomic # 30
Atomic mass- 65.409g
Symbol- Zn
protons = electrons,
so 30 protons,30 electrons and 35 neutrons.
The atomic mass is also found by adding the protons and neutrons.
It can be found in group 12,period 4. Zinc is a transition metal.
Zinc has an oxidation state of 2+.
Melting point- 420 C
Boiling point- 907 C
Typical compounds formed are: zinc oxide, zinc sulfide and zinc nitrate.
According to records, a German scientists named Andreas Margraf discovered the element in 1746. Even though he was recognized for the discovery, historians agree ancient people created statues with some amount of zinc.
Zinc can be found in united states, Canada and Australia.

Hope this helps! 
6 0
4 years ago
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