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Answer:
<h3>The answer is 0.045 kg/cm³</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass of cylinder = 14 kg
Volume of a cylinder = πr²h
where
r is the radius
h is the height
From the question
h = 25 cm
The volume of the cylinder is
We have
volume = 314.159 cm³
The density of the cylinder is
We have the final answer as
<h3>0.045 kg/cm³</h3>Hope this helps you
Answer: The unusual acidity of cyclopentadiene is because of the fact that on losing a proton it can attain aromaticity and be quite stable.
The conjugate base of cyclopentadiene is aromatic.
Explanation:
The acidity of a molecule can be explained in terms of stability of its conjugate base anion.
So greater the stabilization of conjugate base anion greater the acidity of the molecule.
In case of cyclopentadiene as soon as we abstract a proton from the sp³ hybridised carbon atom ,it leads to a formation of a carbanion and hybridisation of the carbon atom changes from sp³ to sp²and hence now the molecular becomes planar. The negative charge on the carbanion is in the p-orbital and hence now this negative charge can be in conjugation with the 4π electrons available in the system and be delcoalized over the whole ring and now there are 6π electrons available.
Intially the number of π eletcrons=4
after proton abstraction number of π eletcrons=6
The rule for aromaticity comes from the Huckels rule that the system must have 4n+2π electrons.
After the deprotonation molecule has 4n+2π electrons with n=1.
This delocalization of the negative charge over the whole ring leads to increment in the π electrons of the molecule and the molecule from being anti-aromatic becomes aromatic.
So the attainment of aromaticity after losing a proton leads to a high acidity of cyclopentadiene.
Kinly find in attachment the structure and electron delocalisation of π electrons.
If you need help reading it then ask away, the two answers end up being, 2Na, and 2NO3
