Complete question:
Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent C___________________71
H2__________________5.6
N2__________________1.6
S____________________2.7
Ash__________________6.1
O2___________________13
Answer:
LHV = 28478.8 KJ/kg
Explanation:
The gross heating value is also the higher heating value (HHV), while the net heating value is the lower heating value (LHV).
This involves the conversion from higher heating value (HHV) to lower heating value(LHV).
Let's use the formula:
LHV = HHV - 0.212H - 0.0245M - 0.008A
We are given
HHV = 29,770 KJ/kg = 29.770MJ/kg
H = hydrogen% =5.6%
A = oxygen% = 13%
M = 0
Substituting the figures in the formula, we have:
LHV = 29.770 - 0.212*5.6 - 0.0245*0 - 0.008*13
= 29.770 - 1.1872 - 0 - 0.104
= 28.4788 MJ/kg
= 28478.8 KJ/kg
LHV = 28478.8 KJ/kg
The net heating value, LHV = 28478.8 KJ/kg
It is logical to assume that they hydrogen ion concentration in an aqueous solution of a strong monoproctic acid equals the molarity of the acid because ions which are charged,for example ammonium ion (NH4+), which can be derived by the addition of a proton to a molecular base.
Answer:
Option C :
a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio
Explanation:
Empirical Formula:
Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.
So,
Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule
For Example
C₂H₆O₂ Consist of Carbon (C), Hydrogen (H), and Oxygen (O)
Now
Look at the ratio of these three atoms in the compound
C : H : O
2 : 6 : 2
Divide the ratio by two to get simplest ratio
C : H : O
2/2 : 6/2 : 2/2
1 : 3 : 1
So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1
So the empirical formula will be
Empirical formula of C₂H₆O₂ = CH₃O
So, Option C is correct :
a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio
Answer:The answer is D.1,3
Explanation:
