3 years ago

Please Help!!! It’s an emergency. I will make you brainiest!!!

Mathematics

2 answers:

Scrat [10]3 years ago

8 0

Yep that’s correct! Good job!

murzikaleks [220]3 years ago

7 0

3108.3 is the correct answer you’re supposed to divide the circumference by pie

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4 years ago

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Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

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Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

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therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

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3 years ago

21) Rearrange the formula c2 = a2 + b2 for b.

Anvisha [2.4K]

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4 years ago

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Step-by-step explanation:

Given that

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similarly

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