Climate is the average weather type throughout the year while weather is something that can happen just once a day, not the average though.
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
Answer:
It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.
Explanation:
The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.
One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light
Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.
Answer: The atomic mass of a Europium atom is 151.96445 amu.
From the given information:
Percent intensity is 91.61% of Europium atom of molecular weight 150.91986 amu.
Percent intensity is 100.00% of Europium atom of molecular weight 152.92138 amu.
Abundance of Eu-151 atom:
![X_{Eu-151}=\frac{0.9161}{0.9161+1.000}=0.4781](https://tex.z-dn.net/?f=X_%7BEu-151%7D%3D%5Cfrac%7B0.9161%7D%7B0.9161%2B1.000%7D%3D0.4781)
Abundance of Eu-153 atom:
![X_{Eu-153}=\frac{1.000}{0.9161+1.000}=0.5219](https://tex.z-dn.net/?f=X_%7BEu-153%7D%3D%5Cfrac%7B1.000%7D%7B0.9161%2B1.000%7D%3D0.5219)
Atomic mass of Europium atom:
![A=(X_{Eu-151}\times150.91986+X_{Eu-153}\times152.92138)amu\\A=(0.4781\times150.91986+0.5219\times152.92138)amu=151.96445 amu](https://tex.z-dn.net/?f=A%3D%28X_%7BEu-151%7D%5Ctimes150.91986%2BX_%7BEu-153%7D%5Ctimes152.92138%29amu%5C%5CA%3D%280.4781%5Ctimes150.91986%2B0.5219%5Ctimes152.92138%29amu%3D151.96445%20amu)
Therefore, the atomic mass of a Europium atom is 151.96445 amu.
Answer:
we got time and velocity over time.
so the distance is again the area underneath the graph
for a triangle with known base and height it's
4*10 / 2
distance traveled is 20
deceleration occurs when velocity decreases. that happens from t=2 till t=4
in 2 time-units we loose 10 units of velocity, so we decelerate by 5 units per 1 time
a (from t=2 to t=4) = -5v/t