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N76 [4]
3 years ago
11

Encontrar el peso de un elefante cuya masa es de 4500kg. Recordar que la gravedad es de 9.8m/s2

Physics
2 answers:
dusya [7]3 years ago
7 0

la respuesta es 459.183673 kg s2 / m

qwelly [4]3 years ago
7 0

Answer:

44,100 N

Explanation:

4500(9.8) = 44,100

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According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

F=k_e\frac{q_1q_2}{r^2}

where,

F = electrostatic force of attraction or repulsion

k_e = Coulomb's constant

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First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2       ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}     ...........(2)

Equation equation 1 and 2, we get

\frac{F_{sq}}{F_{sp}}=\frac{1}{4}

F_{sq}=4\times F_{sp}

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

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The dimension is L

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In this equation \pi is a dimensionless quantity, and the unit of v is m^{3}.

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