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andriy [413]
3 years ago
10

math problem At a nba game the ratio of the score of team b was 16.21. of a team a got 80 points. how many points did team b get

?
Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

105 points.

Step-by-step explanation:

The scores of team A and B is 16 and 21.

if 16 = 80, The ratio of 16 to 21 is 5.

So, that means 16 x 5 is 80.

How many points did team B get?

score x gap between 16 to 21

= 21 x 5 = 105.

the team B got 105 points.

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Help me solve this pleaseeee
MaRussiya [10]

Answer:

f(n) = 6n + 12

Step-by-step explanation:

There is a common difference in consecutive number of seats, that is

42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 18 and d = 6 , then

f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12

5 0
3 years ago
Sally left the city for vacation. Sara left 5 hours later going 58 mph faster to catch up.
tensa zangetsu [6.8K]

Answer:46.2

Step-by-step explanation:

hope this helps

6 0
3 years ago
What is the y in 10.3=0.6y
ollegr [7]
Hello, you would divide 10.3 by 0.6 to get 17.166 repeating. So y equals 17.166.

6 0
3 years ago
Is trapezoid ABDC the result of a dilation of trapezoid MNPQ by a scale factor of ? Why or why not?
Nady [450]

Answer:

No, because AB is 2/5 the length MN but CD is 1/3 the length QP.  

Step-by-step explanation:

Comparing the corresponding sides, the length of AB is 4.  The length of MN is 10.  This makes their ratio 4/10 = 2/5.

The length of CD is 2.  The length of QP is 6.  this makes their ratio 2/6 = 1/3.

The ratios of the sides are not the same, so the figure is not proportional and is therefore not a dilation.

8 0
3 years ago
Read 2 more answers
HELP!!!!!
Sonja [21]
First off, let's convert the decimal to a fraction, notice, we have two decimals, so we'll use in the denominator, a 1 with two zeros then, two decimals, two zeros, thus   \bf 1.\underline{75}\implies \cfrac{175}{1\underline{00}}\implies \cfrac{7}{4}\implies \stackrel{ratio}{7:4}

now, we know then the ratio dimensions for the new photograph, 

\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{7}{4}\implies \cfrac{4+3}{4}\implies \cfrac{4}{4}+\cfrac{3}{4}\implies 1+\boxed{\cfrac{3}{4}}\impliedby \textit{perimeter is }\frac{3}{4}\textit{ larger}
\\\\\\
\stackrel{areas'~ratio}{\cfrac{s^2}{s^2}}\implies \cfrac{3^2}{4^2}\implies \cfrac{9}{16}\impliedby \textit{area is }\frac{9}{16}\textit{ larger than original}
6 0
3 years ago
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