Question

1. According to the following balanced chemical equation, how many moles of iron will react with 0.455 moles of chlorine? 2Fe(s) + 3Cl2(g) → 2FeCl3(s)

Answer 1

Answer:

$\boxed{ \text{0.303 mol}}$

Explanation:

(a) Balanced equation

2Fe + 3Cl₂ ⟶2FeCl₃

(b) Calculation

You want to convert moles of Cl₂ to moles of Fe.

The molar ratio is 2 mol Fe:3 mol Cl₂

$\text{Moles of Fe} =\text{0.455 mol Cl _{2} } \times \dfrac{\text{2 mol Fe}}{\text{3 mol Cl _{2} }} = \textbf{0.303 mol Fe}\\\\\boxed{ \textbf{0.303 mol of Fe}}\text{ will react.}$